#把一切简单化

如果需要两个列表保持相同的顺序，请尝试以下方法：

bool isSame = a.every((item) => item == b[a.indexOf(item)]);
//List `a` is getting compared with list `b`.

如果你不需要有完全相同的顺序项目，你可以试试这个：

bool isSame = a.every((item) => b.contains(item));
//List `a` is getting compared with list `b`.

现在你可以试着找出你的方法来创造一个结果，并在这个过程中学习。祝你好运。👍

所以我已经在下面的代码中记录了我想说的话。但是这里有一个快速的。
首先，注意我认为listEquals不再受支持，您必须创建过滤条件。
这很简单也很复杂。没有办法不输入变量名或者不写一个新类就得到变量名。好吧，深入看看我做了什么。我会努力让事情变得简单和强大。
此外，在发布带有代码库的问题时，始终使用文本区域中的**“代码示例**，而不是**“Blockquote”**。
如果你需要进一步的帮助，请告诉我。

// First, note that I don't think `listEquals` is in support anymore. You will have
// create your filter condition.
// This is easy and complex. There is no way to get a variable name without
// typing them or writing a new class writing a new function. Well, deep in 
// and see what I did. I will try and make Things easy and strong.

void main() {
  //   I changed to type `Box` to `String` as we are getting a string input
  late List<String> opaqueBoxes = [
    "1",
    "15",
    "2",
    "3",
    "14",
    "13",
    "4",
    "12",
    "5",
    "6",
    "11",
    "10",
    "7",
    "9",
    "8"
  ];

  // Lists to filter against. Added type casting
  final List<String> normalList = [
    "1",
    "2",
    "3",
    "4",
    "5",
    "5",
    "6",
    "7",
    "8",
    "9",
    "10",
    "11",
    "12",
    "13",
    "14",
    "15"
  ];
  final List<String> protanList = [
    "15",
    "14",
    "1",
    "2",
    "13",
    "12",
    "3",
    "4",
    "11",
    "10",
    "5",
    "6",
    "9",
    "8",
    "7"
  ];
  final List<String> deutanList = [
    "1",
    "15",
    "2",
    "3",
    "14",
    "13",
    "4",
    "12",
    "5",
    "6",
    "11",
    "10",
    "7",
    "9",
    "8"
  ];
  final List<String> tritanList = [
    "1",
    "2",
    "3",
    "4",
    "5",
    "6",
    "7",
    "15",
    "8",
    "14",
    "9",
    "13",
    "10",
    "11",
    "12"
  ];

  // transform your list-based filter to list of objects based for easy filtering
  final List allFilterList = [
    {"name": "normal", "list": normalList},
    {"name": "protan", "list": protanList},
    {"name": "deutan", "list": deutanList},
    {"name": "tritan", "list": tritanList},
  ];

  // result output
  String result = "No such list!";

  for (Map list in allFilterList) {
    // filter using `any` Function from dart `List` class
    bool filter = opaqueBoxes.any((item) => list["list"].contains(item));
    if (filter) result = list["name"];
  }

  print("result: $result"); // result: tritan
}