要解析您的输入，请使用以下代码。

function ParseDMS(input) {
    var parts = input.split(/[^\d\w]+/);
    var lat = ConvertDMSToDD(parts[0], parts[1], parts[2], parts[3]);
    var lng = ConvertDMSToDD(parts[4], parts[5], parts[6], parts[7]);
}

以下操作将把DMS转换为DD

function ConvertDMSToDD(degrees, minutes, seconds, direction) {
    var dd = degrees + minutes/60 + seconds/(60*60);

    if (direction == "S" || direction == "W") {
        dd = dd * -1;
    } // Don't do anything for N or E
    return dd;
}

因此，您的输入将生成以下内容：

36°57'9" N  = 36.9525000
110°4'21" W = -110.0725000

十进制坐标可以通过GLatLng(lat, lng)（Google Maps API）输入GoogleMap以获取点

更正了上述函数并将输出设为对象。

function ParseDMS(input) {
    var parts = input.split(/[^\d\w\.]+/);    
    var lat = ConvertDMSToDD(parts[0], parts[2], parts[3], parts[4]);
    var lng = ConvertDMSToDD(parts[5], parts[7], parts[8], parts[9]);

    return {
        Latitude : lat,
        Longitude: lng,
        Position : lat + ',' + lng
    }
}

function ConvertDMSToDD(degrees, minutes, seconds, direction) {   
    var dd = Number(degrees) + Number(minutes)/60 + Number(seconds)/(60*60);

    if (direction == "S" || direction == "W") {
        dd = dd * -1;
    } // Don't do anything for N or E
    return dd;
}

我的改进版本将字符串部分强制转换为Numbers，这样它们实际上可以相加而不是连接在一起，它还处理Seconds组件中常见的十进制值：

function ParseDMS(input) {
    var parts = input.split(/[^\d\w\.]+/);
    var lat = ConvertDMSToDD(parts[0], parts[1], parts[2], parts[3]);
    var lng = ConvertDMSToDD(parts[4], parts[5], parts[6], parts[7]);
}

以下操作将把DMS转换为DD

function ConvertDMSToDD(degrees, minutes, seconds, direction) {
    var dd = Number(degrees) + Number(minutes)/60 + Number(seconds)/(60*60);

    if (direction == "S" || direction == "W") {
        dd = dd * -1;
    } // Don't do anything for N or E
    return dd;
}

以下是我对此看法：

function parse_gps( input ) {

if( input.indexOf( 'N' ) == -1 && input.indexOf( 'S' ) == -1 &&
    input.indexOf( 'W' ) == -1 && input.indexOf( 'E' ) == -1 ) {
    return input.split(',');
}

var parts = input.split(/[°'"]+/).join(' ').split(/[^\w\S]+/);

var directions = [];
var coords = [];
var dd = 0;
var pow = 0;

for( i in parts ) {

    // we end on a direction
    if( isNaN( parts[i] ) ) {

        var _float = parseFloat( parts[i] );

        var direction = parts[i];

        if( !isNaN(_float ) ) {
            dd += ( _float / Math.pow( 60, pow++ ) );
            direction = parts[i].replace( _float, '' );
        }

        direction = direction[0];

        if( direction == 'S' || direction == 'W' )
            dd *= -1;

        directions[ directions.length ] = direction;

        coords[ coords.length ] = dd;
        dd = pow = 0;

    } else {

        dd += ( parseFloat(parts[i]) / Math.pow( 60, pow++ ) );

    }

}

if( directions[0] == 'W' || directions[0] == 'E' ) {
    var tmp = coords[0];
    coords[0] = coords[1];
    coords[1] = tmp;
}

return coords;

}
此函数并不处理所有类型的lat / long类型，但它处理以下格式：

-31,2222,21.99999
-31 13 13 13.75S, -31 13 13 13.75W
-31 13 13 13.75S -31 13 13 13.75W
-31 13 13 13.75W -31 13.75S
36°57'9" N 110°4'21" W
110°4'21" W 36°57'9"N

这正是我需要的。

我在这个函数上得到了一些NaN，需要这样做（不要问我为什么）

function ConvertDMSToDD(days, minutes, seconds, direction) {
    var dd = days + (minutes/60) + seconds/(60*60);
    dd = parseFloat(dd);
    if (direction == "S" || direction == "W") {
        dd *= -1;
    } // Don't do anything for N or E
    return dd;
}

我使用了**\d+（\，\d+）和\d+（.\d+）**，因为可以有浮点数
我的最后一个功能：

convertDMSToDD: function (dms) {
     let parts = dms.split(/[^\d+(\,\d+)\d+(\.\d+)?\w]+/);
     let degrees = parseFloat(parts[0]);
     let minutes = parseFloat(parts[1]);
     let seconds = parseFloat(parts[2].replace(',','.'));
     let direction = parts[3];

     console.log('degrees: '+degrees)
     console.log('minutes: '+minutes)
     console.log('seconds: '+seconds)
     console.log('direction: '+direction)

     let dd = degrees + minutes / 60 + seconds / (60 * 60);

     if (direction == 'S' || direction == 'W') {
       dd = dd * -1;
     } // Don't do anything for N or E
     return dd;
   }

Joe，你提到的脚本已经做了你想要的。有了它，你可以转换纬度和经度，并把它放到链接中，以查看谷歌Map中的位置：

var url = "http://maps.google.com/maps?f=q&source=s_q&q=&vps=3&jsv=166d&sll=" + lat.parseDeg() + "," + longt.parseDeg()

使用Shannon Antonio Black的正则表达式模式（见上图），我的解是：

function convertLatLong(input) {

if(!( input.toUpperCase() != input.toLowerCase()) ) {   // if geodirection abbr. isn't exist, it should be already decimal notation
    return `${input}:the coordinate already seems as decimal`
}
const parts = input.split(/[°'"]+/).join(' ').split(/[^\w\S]+/); // thanks to Shannon Antonio Black for regEx patterns 
const geoLetters = parts.filter(el=> !(+el) ) 
const coordNumber = parts.filter(n=>(+n)).map(nr=>+nr)
const latNumber = coordNumber.slice(0,(coordNumber.length/2))
const longNumber = coordNumber.slice((coordNumber.length/2))
const reducer = function(acc,coord,curInd){
   return acc + (coord/Math.pow( 60, curInd++ ))
}
let latDec = latNumber.reduce(reducer)
let longDec = longNumber.reduce(reducer)

if(geoLetters[0].toUpperCase()==='S') latDec = -latDec // if the geodirection is S or W, decimal notation should start with minus
if(geoLetters[1].toUpperCase()==='W') longDec= -longDec 

const dec= [{
    ltCoord: latDec,
    geoLet:geoLetters[0]
},
{
    longCoord: longDec,
    geoLet: geoLetters[1]
}]

return dec
}

我认为EC6是更简化的版本