使用ecmaScript-5可以执行以下操作：

var arr = [{ id: 1, level: 0, name: 'A' },{ id: 2, level: 1, name: 'B' },{ id: 3, level: 1, name: 'S' },{ id: 4, level: 0, name: 'A' },{ id: 5, level: 0, name: 'S' },{ id: 6, level: 1, name: 'A' },{ id: 7, level: 0, name: 'B' },]

var result = arr.filter(function (obj) {
  return obj.level === 1 || ['B', 'S'].indexOf(obj.name) > -1;
})

console.log(result)

一个简单的循环就可以实现这一点-并将匹配的项推入一个新的数组中，该数组将包含所需的项。

我已经避免了使用更新的、更令人兴奋的方法来实现旧的var和forEach方法，以满足您的ecma-5要求。

var arr = [
{id: 1, level: 0, name: 'A'},
{id: 2, level: 1, name: 'B'},
{id: 3, level: 1, name: 'S'},
{id: 4, level: 0, name: 'A'},
{id: 5, level: 0, name: 'S'},
{id: 6, level: 1, name: 'A'},
{id: 7, level: 0, name: 'B'}, ]

var newArr = [];

arr.forEach(function(item) {
  if(item.level === 1 || (item.name === 'A' || item.name ==='B')) {
   newArr.push(item)
  }
})

console.log(newArr);

//gives[
  //{id: 1,level: 0, name": "A"},
  //{id: 2, level: 1, name: "B"},
  //{id: 3, level: 1, name: "S"},
  //{id: 4, level: 0, name: "A"},
  //{id: 6, level: 1, name: "A"},
  //{id: 7, level: 0, name: "B"}]

const arr = [
  { id: 1, level: 0, name: 'A' },
  { id: 2, level: 1, name: 'B' },
  { id: 3, level: 1, name: 'S' },
  { id: 4, level: 0, name: 'A' },
  { id: 5, level: 0, name: 'S' },
  { id: 6, level: 1, name: 'A' },
  { id: 7, level: 0, name: 'B' },
];

const newArr = arr.filter(
  item => item.level === 0 || item.name === 'B' || item.name === 'S'
);

console.log(newArr);

可以将Array.prototype.filter()方法与Array.prototype.indexOf()方法沿着使用，以根据条件筛选数组：

const array = [
  {id: 1, level: 0, name: 'A'},
  {id: 2, level: 1, name: 'B'},
  {id: 3, level: 1, name: 'S'},
  {id: 4, level: 0, name: 'A'},
  {id: 5, level: 0, name: 'S'},
  {id: 6, level: 1, name: 'A'},
  {id: 7, level: 0, name: 'B'},
];

var names = ['B', 'S'];

var result = array.filter(item => item.level === 0 || names.indexOf(item.name) !== -1);

console.log(result)