CREATE FUNCTION [dbo].[MaxOrNull](@val1 int, @val2 int)
returns int
as
begin
if @val1 >= @val2 RETURN @val1
if @val1 < @val2 RETURN @val2
RETURN NULL
end
Create FUNCTION [dbo].[MaxOf]
(
@val1 INT =0,
@val2 INT=0 ,
@val3 INT =0,
@val4 INT =0,
@val5 INT =0,
@val6 INT =0,
@val7 INT =0,
@val8 INT =0,
@val9 INT =0,
@val10 INT =0,
@val11 INT =0,
@val12 INT =0,
@val13 INT =0,
@val14 INT =0,
@val15 INT =0,
@val16 INT =0,
@val17 INT =0,
@val18 INT =0,
@val19 INT =0,
@val20 INT =0)
--OUTPUT
RETURNS INT WITH SCHEMABINDING
AS
BEGIN
DECLARE @MAX AS INT ;
SET @MAX=0
IF isnull(@val1,0)> isnull(@MAX,0) SET @MAX=isnull(@val1,0)
IF isnull(@val2,0)> isnull(@MAX,0) SET @MAX=isnull(@val2,0)
IF isnull(@val3,0)> isnull(@MAX,0) SET @MAX=isnull(@val3,0)
IF isnull(@val4,0)> isnull(@MAX,0) SET @MAX=isnull(@val4,0)
IF isnull(@val5,0)> isnull(@MAX,0) SET @MAX=isnull(@val5,0)
IF isnull(@val6,0)> isnull(@MAX,0) SET @MAX=isnull(@val6,0)
IF isnull(@val7,0)> isnull(@MAX,0) SET @MAX=isnull(@val7,0)
IF isnull(@val8,0)> isnull(@MAX,0) SET @MAX=isnull(@val8,0)
IF isnull(@val9,0)> isnull(@MAX,0) SET @MAX=isnull(@val9,0)
IF isnull(@val10,0)> isnull(@MAX,0) SET @MAX=isnull(@val10,0)
IF isnull(@val11,0)> isnull(@MAX,0) SET @MAX=isnull(@val11,0)
IF isnull(@val12,0)> isnull(@MAX,0) SET @MAX=isnull(@val12,0)
IF isnull(@val13,0)> isnull(@MAX,0) SET @MAX=isnull(@val13,0)
IF isnull(@val14,0)> isnull(@MAX,0) SET @MAX=isnull(@val14,0)
IF isnull(@val15,0)> isnull(@MAX,0) SET @MAX=isnull(@val15,0)
IF isnull(@val16,0)> isnull(@MAX,0) SET @MAX=isnull(@val16,0)
IF isnull(@val17,0)> isnull(@MAX,0) SET @MAX=isnull(@val17,0)
IF isnull(@val18,0)> isnull(@MAX,0) SET @MAX=isnull(@val18,0)
IF isnull(@val19,0)> isnull(@MAX,0) SET @MAX=isnull(@val19,0)
IF isnull(@val20,0)> isnull(@MAX,0) SET @MAX=isnull(@val20,0)
RETURN @MAX ;
END
5条答案
按热度按时间qlvxas9a1#
SQL Server 2008中没有,但
GREATEST
和LEAST
函数现在可用于SQL Server 2022和SQL Server的云版本对于以前的版本,您可以使用子查询可以访问外部查询中的列这一事实,这样您就可以添加一个子查询从这些查询的并集中选择
max
。或用于SQL Server 2000/2005
kwvwclae2#
为此,我创建了一个标量函数,如下所示:
这是最优雅的解决方案,可以在SQL代码中的任何地方使用。
ykejflvf3#
我建议采用以下解决方案:
i7uaboj44#
可能的解决方案:
电话号码应该是
vltsax255#
请尝试使用
TOP
或MAX
。