如何在typescript中发送一个handleSubmit on react钩子表单？

zaqlnxep 于 2023-01-10 发布在 TypeScript

关注(0)|答案(2)|浏览(124)

我正在使用typescript和react进行表单注册，但是，当我尝试提交handleSignup函数时，我遇到了一个键入错误。

import { useForm } from "react-hook-form";
import * as yup from "yup";
import { yupResolver } from "@hookform/resolvers/yup";
import { api } from "../../services/api";

export const Signup = () => {

    const schema = yup.object().shape({
        name: yup.string(), 
        email: yup.string(),
        password: yup.string(),
        address: yup.object().shape({
            zipCode: yup.string(),
            number: yup.number(),
            complement: yup.string(),
        })
    })
    
    interface signUpCredentials {
        name: string 
        email: string
        password: string 
        address: {
            zipCode: string 
            number: number 
            complement: string 
        } 
    }

    const {
        register,
        formState: { errors },
        handleSubmit,
    } = useForm({
        resolver: yupResolver(schema)
    })

    const handleSignup = ({ address, email, name, password }: signUpCredentials ) => {
        api
            .post("/users/signup", { address, email, name, password })
            .then((response) => {
                console.log("Created")
            })
            .catch((err) => {
                console.error("Not created")
            })
    }

    return (
        <form
            onSubmit={handleSubmit(handleSignup)}
        >
            <input
                {...register("name")}
                placeholder="name"
            />
            <input
                {...register("email")}
                placeholder="email"
            />
            <input
                {...register("password")}
                placeholder="password"
            />
            <input
                {...register("address.zipCode")}
                placeholder="zipCode"
            />
            <input
                {...register("address.number")}
                placeholder="number"
            />
            <input
                {...register("address.complement")}
                placeholder="complement"
            />
            <button type="submit" >
                Submit
            </button>
        </form>
    )
}

我面临的问题正是 *
onSubmit = {处理提交（处理注册）}
我正在接收：
类型为"（{地址、电子邮件、名称、密码}：signUpCredentials）=〉void "不能赋给类型为" SubmitHandler "的参数。参数" __0 "和" data "的类型不兼容。类型"{[ x：字符串]：任意; "}"缺少类型" signUpCredentials "的以下属性：名称、电子邮件、密码、地址（2345）

typescript

来源：https://stackoverflow.com/questions/72638620/how-to-send-a-handlesubmit-on-react-hook-form-in-typescript

2条答案

按热度按时间

6ie5vjzr1#

你还没有给useForm钩子指定类型变量signUpCredentials，你应该把onSubmit处理程序改为handleSignup，并在里面调用handleSubmit。

import { useForm } from "react-hook-form";
import * as yup from "yup";
import { yupResolver } from "@hookform/resolvers/yup";
import { api } from "../../services/api";

export const Signup = () => {

    const schema = yup.object().shape({
        name: yup.string(), 
        email: yup.string(),
        password: yup.string(),
        address: yup.object().shape({
            zipCode: yup.string(),
            number: yup.number(),
            complement: yup.string(),
        })
    })
    
    interface signUpCredentials {
        name: string 
        email: string
        password: string 
        address: {
            zipCode: string 
            number: number 
            complement: string 
        } 
    }

    const {
        register,
        formState: { errors },
        handleSubmit,
    } = useForm<signUpCredentials>({
        resolver: yupResolver(schema)
    })

    const handleSignup = handleSubmit(data: signUpCredentials) => {
          console.log(data)
          // do api stuff here
    }

    return (
        <form
            onSubmit={handleSignup}
        >
            <input
                {...register("name")}
                placeholder="name"
            />
            <input
                {...register("email")}
                placeholder="email"
            />
            <input
                {...register("password")}
                placeholder="password"
            />
            <input
                {...register("address.zipCode")}
                placeholder="zipCode"
            />
            <input
                {...register("address.number")}
                placeholder="number"
            />
            <input
                {...register("address.complement")}
                placeholder="complement"
            />
            <button type="submit" >
                Submit
            </button>
        </form>
    )
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>

为了更好地理解，我创建了一个Code Sandbox链接，其中删除了指向服务的import语句，因为我们没有该语句，您可以通过检查控制台看到调用函数时没有任何警告/错误。

参考：React Hook form (TS)

赞(0）回复(0）举报 2023-01-10

fcwjkofz2#

不需要像@sri-vineeth提到的那样修改onSubmit，只需要使用SubmitHandler类型即可。

const handleSignup: SubmitHandler<SignUpCredentials> = ({ address, email, name, password }) => {
  ...
}

另外请注意接口和类型应该使用PascalCase。因此将signUpCredentials更改为SignUpCredentials。

赞(0）回复(0）举报 2023-01-10

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如何在typescript中发送一个handleSubmit on react钩子表单？

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