我是新的PHP和学习它！
我在本地主机名“submitpaper”上创建了一个简单的数据库
然后，我创建了一个名为'upload_file'的表，它有两个字段（file 1、file 2），它们都是（VARCHAR 255）
将文件保存到目标文件夹“testupload”时遇到问题
请检查并查看我的PHP脚本和HTML
PHP脚本
<?php
//This is the directory where files will be saved
$target = "testupload/";
$target = $target . basename( $_FILES['file']['name']);
//This gets all the other information from the form
$file1=($_FILES['file1']['name']);
$file2=($_FILES['file2']['name']);
// Connects to your Database
mysql_connect("localhost", "root", "")
//Writes the information to the database
mysql_query("INSERT INTO `upload_file` VALUES ('$file1', '$file2')") ;
//Writes the photo to the server
if(move_uploaded_file($_FILES['file']['tmp_name'], $target)) {
//Tells you if its all ok
echo "The file ". basename( $_FILES['uploadedfile']['name']). "has been uploaded, and your information has been added to the directory"; }
else {
//Gives and error if its not echo "Sorry, there was a problem uploading your file."; }
?>HTML文件代码
<html>
<body>
<form action="upload_file.php" method="post"
enctype="multipart/form-data">
File1:<input type="file" name="file1" id="file1"><br>
File2:<input type="file" name="file2" id="file2">
<input type="submit" name="submit" value="Submit">
</form>
</body>
2条答案
按热度按时间bfnvny8b1#
您试图在
$_FILES['file']['name']中错误地访问文件名。您必须使用$_FILES['nameoffile']['name']，其中nameoffile是您为文件输入字段指定的文件名。例如，代码：
hmmo2u0o2#
下面的代码可能对您有用。
在此之前，您必须对文件上载路径文件夹具有读写权限。