我有一个jQuery数据表填充了来自db '表的信息,我隐藏了两列,现在我需要从两个隐藏列中获取值,但我不能,这是我的数据表的代码,并设置了属性visible:最后两列为false
$('#myTable').DataTable({
searching: false,
paging: true,
responsive: true,
ordering: false,
bInfo: false,
bLengthChange: false,
processing: true,
info: false,
deferRender: true,
orderMulti: false,
"ajax": {
"url": "../home/CargarTabla?id=" + noDocumento,
"type": "GET",
"datatype": "json"
},
"columns": [
{ "data": "nombres", "autoWidth": true, "orderable": false },
{ "data": "apellidos", "autoWidth": true, "orderable": false },
{ "data": "dui", "autoWidth": true, "orderable": false },
{ "data": "numero_isss", "autoWidth": true, "orderable": false },
{ "data": "cargo_participante", "autoWidth": true, "orderable": false },
{ "data": "genero", "autoWidth": true, "orderable": false, "visible": false },
{ "data": "nivel_puesto", "autoWidth": true, "orderable": false, "visible": false },
{ "defaultContent": " <a href='#' id='select'>Modificar</a> ", "autoWidth": true, "orderable": false }
],
"oLanguage": {
"sEmptyTable": "No hay registros disponibles",
"sInfo": " _TOTAL_ registros. Mostrando de (_START_ a _END_)",
"sLoadingRecords": "Por favor espera - Cargando...",
"sSearch": "Filtro:",
"sLengthMenu": "Mostrar _MENU_",
"oPaginate": {
"sLast": "Última página",
"sFirst": "Primera",
"sNext": "Siguiente",
"sPrevious": "Anterior"
},
"oAria": {
"sSortAscending": ": Activar para ordenar la columna de manera ascendente",
"sSortDescending": ": Activar para ordenar la columna de manera descendente"
}
}
});
这就是我从用户可见的列中获取值的方法,它工作得很好:
$("#myTable").on('click', '#select', function (e) {
e.preventDefault();
var currentRow = $(this).closest("tr");
var Nombres = currentRow.find("td:eq(0)").text();
var Apellidos = currentRow.find("td:eq(1)").text();
var DUI = currentRow.find("td:eq(2)").text();
var ISSS = currentRow.find("td:eq(3)").text();
var Cargo = currentRow.find("td:eq(4)").text();
alert(Nombres + Apellidos + DUI +ISSS+ Cargo);
});
但是如何从隐藏列中获取值呢?我已经在$("#myTable").on('click', '#select', function (e)
中尝试过了,但没有成功
alert(table.row(this).data()[5]);
alert(table.row(this).data()[6]);
另一种方法没有成功
var row = $(this).parents("td")[0];
var pos = oTable.fnGetPosition(row);
var Genero = oTable.fnGetData(pos[5])["idGenero"];
最后
var arr = $('#myTable').dataTable().fnGetData($(currentRow));
var Genero = arr[5];
var Nivel = arr[6];
你能帮我从隐藏的列中得到值吗?2顺便说一句,这是HTML代码
<div class="table-responsive">
<table class="table table-striped table-condensed" id="myTable" style="width:100%; margin:0 auto;">
<thead>
<tr>
<th>Nombres</th>
<th>Apellidos</th>
<th>DUI</th>
<th>ISSS</th>
<th>Cargo</th>
<th>Sexo</th>
<th>Nivel</th>
<th></th>
</tr>
</thead>
<tbody></tbody>
</table>
</div>
4条答案
按热度按时间plupiseo1#
使用下面的代码:
nbnkbykc2#
如何获取表中所有的
td
值:它们将存储在数组
tdItems
中。n6lpvg4x3#
使用jQuery Datatable API函数获取包括隐藏列在内的完整行数据-
首先获取datatable的示例,然后执行函数以获取完整的行数据。例如,您希望在单击特定行时获取完整的行数据,下面的代码可以帮助fnDrawCallback回调函数中的表-
谢谢
a7qyws3x4#
我知道你的问题很老了,但如果有人还有问题,试试这个: