如何从对象中获取数据?我需要从dataValues中获取数据 然后写下来
const user = User.findOne({
}).then(e=>console.log(e))
User {
dataValues: {
id: 1,
firstName: 'Мен',
lastName: 'Bezrukov',
login: 'qqq',
password: '1234',
role: 'admin',
ip: '12345',
descipt: 'developer',
o_sebe: 'top man',
soc_set: 'vk',
age: '17',
likes__foto: '5',
coment__foto: null,
createdAt: 2023-01-15T09:06:39.000Z,
updatedAt: 2023-01-15T09:07:00.000Z
},
_previousDataValues: {
id: 1,
firstName: 'Мен',
lastName: 'Bezrukov',
login: 'qqq',
password: '1234',
role: 'admin',
ip: '12345',
descipt: 'developer',
o_sebe: 'top man',
soc_set: 'vk',
age: '17',
likes__foto: '5',
coment__foto: null,
createdAt: 2023-01-15T09:06:39.000Z,
updatedAt: 2023-01-15T09:07:00.000Z
},
uniqno: 1,
_changed: Set(0) {},
isNewRecord: false,
_schema: null,
_schemaDelimiter: '',
raw: true,
attributes: [
'id', 'firstName',
'lastName', 'login',
'password', 'role',
'ip', 'descipt',
'o_sebe', 'soc_set',
'age', 'likes__foto',
'coment__foto', 'createdAt',
'updatedAt'
]
},
}
1条答案
按热度按时间eimct9ow1#
您可以通过user.id、用户名或解构直接访问数据:
另一个选项是放置原始:没错。