我试图使impl AsRef<[u8; 3]>在函数参数中工作。
Playground再现：https://play.rust-lang.org/?version=stable&mode=debug&edition=2021&gist=e99007b0571ed2f088b3e38a6692ccdf
下面是MPE：

fn print_bytes_3(bytes: impl AsRef<[u8; 3]>)
{
    println!("{:?}", bytes.as_ref());
}

pub fn main() {
    let a: [u8; 3] = [1, 2, 3];
    print_bytes_3(a);
}

以上代码无法编译，并显示以下错误消息：

Compiling playground v0.0.1 (/playground)
error[E0277]: the trait bound `[u8; 3]: AsRef<[u8; 3]>` is not satisfied
 --> src/main.rs:8:19
  |
8 |     print_bytes_3(a);
  |     ------------- ^ the trait `AsRef<[u8; 3]>` is not implemented for `[u8; 3]`
  |     |
  |     required by a bound introduced by this call
  |
  = help: the following other types implement trait `AsRef<T>`:
            [T; N]
            [T]
note: required by a bound in `print_bytes_3`
 --> src/main.rs:1:30
  |
1 | fn print_bytes_3(bytes: impl AsRef<[u8; 3]>)
  |                              ^^^^^^^^^^^^^^ required by this bound in `print_bytes_3`

For more information about this error, try `rustc --explain E0277`.
error: could not compile `playground` due to previous error

AsRef文档中写到trait为通用固定大小数组实现：
impl<T, const N: usize> AsRef<[T]> for [T; N]
如果我理解正确的话，编译器似乎无法确定使用AsRef的哪个实现。
在错误消息之后，它与其他trait实现冲突，即impl<T> AsRef<[T]> for [T]：

= help: the following other types implement trait `AsRef<T>`:
            [T; N]
            [T]

经过一些调整后，这段代码可以正常工作：

fn print_bytes_3(bytes: &[u8; 3])
{
    println!("{:?}", bytes);
}

pub fn main() {
    let a: [u8; 3] = [1, 2, 3];
    print_bytes_3(&a);
}

但是，我仍然想利用AsRef所提供的：impl AsRef<[u8; 3]>在我的函数参数，因为它可以接受拥有和借用类型，而无需指定&。
有什么方法可以解决编译器无法确定的歧义吗？或者让我知道我是否做错了什么（我是Rust的新手）。