我需要读取和打印存储在两个变量中的数字（我正在做一个菜单程序），但当我打印它们时，它打印的是ASCII表中的小写字母（如a，b，c，而不是2，3，4）。我知道我应该减去48并乘以48，但我没有找到一个很好的解决方案，如何在我的程序中实现这种转换。我使用的是汇编x86，TASM。
这是阅读输入的代码：
情节：

mov dx, offset prompt1
   mov ah, 9
   int 21h

        input_x:

    mov bx, offset x ; point BX to the start of the array x
    mov cx, 10 ; set the counter to the number of elements in the array x

    input_loop1:
        mov ah, 01h ; function to read a single character
        int 21h ; call DOS function

        mov [bx], al ; store the character in the current array element
        inc bx ; move to the next array element

        loop input_loop1 ; repeat until counter reaches 0

    jmp input_y

        input_y:

mov dx, offset prompt2
mov ah, 9
int 21h

    mov bx, offset y ; point BX to the start of the array y
    mov cx, 10 ; set the counter to the number of elements in the array y

    input_loop2:
        mov ah, 01h ; function to read a single character
        int 21h ; call DOS function

        mov [bx], al ; store the character in the current array element
        inc bx ; move to the next array element

        loop input_loop2 ; repeat until counter reaches 0
    jmp bucla

我认为问题出在我的打印代码上
阿菲萨雷：

mov dx, offset prompt3
   mov ah, 9
   int 21h

  print_x:
    mov bx, offset x ; point BX to the start of the array x
    mov cx, 10 ; set the counter to the number of elements in the array x

    print_loop1:
        mov dl, [bx] ; move the value of the current array element to DL
        add dl, 48 ; convert the number to its ASCII equivalent
       
        mov ah, 02h ; function to print a single character
        int 21h ; call DOS function

        inc bx ; move to the next array element
        loop print_loop1 ; repeat until counter reaches 0

    jmp print_y

  print_y:

 mov dx, offset prompt4
   mov ah, 9
   int 21h

    mov bx, offset y ; point BX to the start of the array y
    mov cx, 10 ; set the counter to the number of elements in the array y

    print_loop2:
        mov dl, [bx] ; move the value of the current array element to DL
        add dl, 48 ; convert the number to its ASCII equivalent

        mov ah, 02h ; function to print a single character
        int 21h ; call DOS function

        inc bx ; move to the next array element
        loop print_loop2 ; repeat until counter reaches 0

jmp bucla ; return to main loop