json 值后的“r”无效,应为,“”、“}”或“]”

nukf8bse  于 2023-01-18  发布在  其他
关注(0)|答案(1)|浏览(112)

我正在尝试将字符串反序列化为具有以下结构的类:

// this is my json
    {
      "MethodName":"PRC_SET_COMMISSION_STATIC",
      "Input":"{"reqType":"U","sapId":17000100,"offerType":5,"commissionRate":4,"accountNo":null,"fromDate":"2022-05-29T00:00:00","toDate":"2029-05-29T00:00:00","userId":"13601360"}"}

这是我的类,我想得到这些值:

public class ProcessRequestRequestModelCl :AuthenticationModelCl
    {
        public string MethodName { get; set; }
        public string Input { get; set; }
    }

所以我要做的是这样的:

ProcessRequestRequestModelCl RequestModel = System.Text.Json.JsonSerializer.Deserialize<ProcessRequestRequestModelCl>(ParameterStr);

但我得到了这个错误:* *“r”在值后无效。应为“,”、“}”或“]”**问题与"Input":"{"reqType":"U","sapId":17000100,"offerType":5,"commissionRate":4,"accountNo":null,"fromDate":"2022-05-29T00:00:00","toDate":"2029-05-29T00:00:00","userId":"13601360"}"有关。我想知道如何将json作为字符串传递给输入值。

osh3o9ms

osh3o9ms1#

如果你真的需要内部json作为一个字符串,你需要如下转义引号:

{
    "MethodName":"PRC_SET_COMMISSION_STATIC",
    "Input": "{\"reqType\":\"U\",\"sapId\":17000100,\"offerType\":5,\"commissionRate\":4,\"accountNo\":null,\"fromDate\":\"2022-05-29T00:00:00\",\"toDate\":\"2029-05-29T00:00:00\",\"userId\":\"13601360\"}"
}

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