我是从MYSQL到ORACLE。
我的JPA身份验证设置为this:
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String email) throws UsernameNotFoundException {
AppUser user = userRepository.findByUseremailIgnoreCase(email);
对于MySQL,一切都很好。但是对于Oracle,在使用JPA身份验证登录期间,我遇到了这个异常。
org.springframework.security.authentication.InternalAuthenticationServiceException: Unable to extract JDBC value for position `3`
以下为例外情况:
Caused by: org.springframework.orm.jpa.JpaSystemException: Unable to extract JDBC value for position `3`
Caused by: java.sql.SQLException: Invalid conversion requested
Caused by: java.lang.IllegalArgumentException: Timestamp format must be yyyy-mm-dd hh:mm:ss[.fffffffff]
有什么线索我错过了什么,在哪里调试?
我的表格结构如下:
create table CONTENTPLUSPLUS.app_user (
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
useremail VARCHAR(150) NOT NULL,
userpassword VARCHAR(150) NOT NULL,
useruuid VARCHAR(50) NOT NULL,
userfirstname VARCHAR(150) NOT NULL,
userlastname VARCHAR(150) NOT NULL,
userenabled NUMBER(1) DEFAULT 0 NOT NULL,
created_by VARCHAR(150) NOT NULL,
created_date VARCHAR(150) NOT NULL,
modified_by VARCHAR(150) NOT NULL,
modified_date VARCHAR(150) NOT NULL,
CONSTRAINT appuser_pk PRIMARY KEY (id), UNIQUE (useremail, useruuid));
create table CONTENTPLUSPLUS.app_role(
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
name VARCHAR(150) NOT NULL,
CONSTRAINT approle_pk PRIMARY KEY (id),UNIQUE (name));
CREATE TABLE CONTENTPLUSPLUS.app_department (
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
departmentuuid VARCHAR(150),
departmentheadname varchar(255) NOT NULL,
departmentheademail varchar(255) NOT NULL,
departmentname varchar(255) NOT NULL,
userid NUMBER NOT NULL,
created_by VARCHAR(150) NOT NULL,
created_date VARCHAR(150) NOT NULL,
modified_by VARCHAR(150) NOT NULL,
modified_date VARCHAR(150) NOT NULL,
CONSTRAINT appdepartment_pk PRIMARY KEY (id),UNIQUE (departmentname, departmentuuid));
CREATE TABLE CONTENTPLUSPLUS.app_user_department (
userid NUMBER NOT NULL,
departmentid NUMBER NOT NULL
);
ALTER TABLE CONTENTPLUSPLUS.app_user_department ADD CONSTRAINT FK_AUSERDEPTUSERID FOREIGN KEY (userid) REFERENCES app_user (id);
ALTER TABLE CONTENTPLUSPLUS.app_user_department ADD CONSTRAINT FK_AUSERDEPTDEPTID FOREIGN KEY (departmentid) REFERENCES app_department (id);
ALTER TABLE CONTENTPLUSPLUS.app_department ADD CONSTRAINT FK_AUSERUSERID FOREIGN KEY (userid) REFERENCES app_user (id);
CREATE TABLE CONTENTPLUSPLUS.app_user_role (
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
userid NUMBER NOT NULL,
roleid NUMBER NOT NULL,
CONSTRAINT appuserrole_pk PRIMARY KEY (id));
ALTER TABLE CONTENTPLUSPLUS.app_user_role ADD CONSTRAINT FK_AURUSERID FOREIGN KEY (userid) REFERENCES app_user (id);
ALTER TABLE CONTENTPLUSPLUS.app_user_role ADD CONSTRAINT FK_AURROLEID FOREIGN KEY (roleid) REFERENCES app_role (id);
下面是在登录操作期间触发的查询(仅针对MySQL显示):
Hibernate:
select
a1_0.id,
a1_0.created_by,
a1_0.created_date,
a1_0.modified_by,
a1_0.modified_date,
a1_0.useremail,
a1_0.userenabled,
a1_0.userfirstname,
a1_0.userlastname,
a1_0.userpassword,
a1_0.useruuid
from
app_user a1_0
where
upper(a1_0.useremail)=upper(?)
Hibernate:
select
r1_0.userid,
r1_1.id,
r1_1.name
from
app_user_role r1_0
join
app_role r1_1
on r1_1.id=r1_0.roleid
where
r1_0.userid=?
1条答案
按热度按时间jvlzgdj91#
将Java中的DateMap到SQL中的VARCHAR2:这是个坏主意。你可能会幸运地使用TS的默认转换格式和MySQL中的语言环境:回到我的第一条评论...看看SQL办公时间会话代码...