Sping Boot mongoDB类查询数字字段-整数/双精度

insrf1ej  于 2023-01-20  发布在  Go
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我想在Spring Boot中对Integer/Double字段进行LIKE查询。
收藏名称:球员

{
    "firstName" : "Lionel",
    "lastName" : "messi",
    "team" : "FC Barcelona",
    "salary" : 40000,
    "type" : "football"
},{
    "firstName" : : "Cristiano",
    "lastName" : "Ronaldo",
    "team" : "Real Madrid C.F.",
    "salary" : 35000,
    "type" : "football"
},{
    "firstName" : : "Neymar",
    "lastName" : "Jr",
    "team" : "Paris Saint-Germain F.C.",
    "salary" : 25000,
    "type" : "football"
},{
    "firstName" : "Luis",
    "lastName" : "Alberto",
    "team" : "FC Barcelona",
    "salary" : 25000,
    "type" : "football"
},{
    "firstName" : "Virat",
    "lastName" : "Kohali",
    "team" : "Indian Cricket Team",
    "salary" : 40000,
    "type" : "cricket"
}

并且我的spring java代码如下,其中生成查询.

String game = "football";
String team = "barcelona";
Double salary = 250;

Query query = new Query();
Set<String> gameType = new HashSet<>();
List<Criteria> andCriteria = new ArrayList<>();

gameType.add(game);

andCriteria.add(Criteria.where("type").in(gameType));
andCriteria.add(Criteria.where("team").regex(team,"i"));

Criteria[] criteriaArray = new Criteria[andCriteria.size()];
criteriaArray = andCriteria.toArray(criteriaArray);
query.addCriteria(new Criteria().andOperator(criteriaArray));

List<Players> players = mongoTemplate.find(query, Players.class);

return players;

质询:

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
        }
    },
    {
      "team": {
        $regex: "barcelona",
        $options: "i"
      }
    }]
})

上面的查询返回了2个文档,"类型"为"足球"和"球队",如 * 巴塞罗那 *

{"firstName" : "Lionel", "lastName" : "messi", "team" : "FC Barcelona", "salary" : 40000, "type" : "football"},
{"firstName" : "Luis", "lastName" : "Alberto", "team" : "FC Barcelona", "salary" : 25000, "type" : "football"}

但我希望查询"类型"为"足球","工资"为 * 250 *

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
      }
    },
    {
      $where : "/^250.*/.test(this.salary)"
    }]
})

并且返回的结果将如下。

{"firstName" : : "Neymar", "lastName" : "Jr", "team" : "Paris Saint-Germain F.C.", "salary" : 25000, "type" : "football"},
{"firstName" : "Luis", "lastName" : "Alberto", "team" : "FC Barcelona", "salary" : 25000, "type" : "football"}

先谢谢你。

ffscu2ro

ffscu2ro1#

我设法建立双字段的LIKE查询。

Query query = new Query();
Set<String> gameType = new HashSet<>();
List<Criteria> andCriteria = new ArrayList<>();

String game = "football";
int salary = 250;   

gameType.add(game);

andCriteria.add(Criteria.where("type").in(gameType));
andCriteria.add(Criteria.where("$where").is("/^" + salary + ".*/.test(this.salary)"));

Criteria[] criteriaArray = new Criteria[andCriteria.size()];
criteriaArray = andCriteria.toArray(criteriaArray);
query.addCriteria(new Criteria().andOperator(criteriaArray));

List<Players> players = mongoTemplate.find(query, Players.class);

return players;

这段代码生成了我上面发布的LIKE。
你也可以用简单的方法来做。

Query query = new Query();
Set<String> gameType = new HashSet<>();
        
String game = "football";
int salary = 250;
        
gameType.add(game);
        
query.addCriteria(Criteria.where("type").in(gameType));
query.addCriteria(Criteria.where("$where").is("/^" + salary + ".*/.test(this.salary)"));

List<Players> players = mongoTemplate.find(query, Players.class);

return players;

质询:

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
      }
    },
    {
      $where : "/^250.*/.test(this.salary)"
    }]
})

我希望这会有所帮助。

j9per5c4

j9per5c42#

根据@Rahul Ghadage的回答,我能够让这个工作:

query.addCriteria(Criteria.where("$where").is("/" + salary + "/.test(this.salary)"));

注意,代码示例中的salary是用要匹配的数字填充的Java变量,第二个salary是mongo结构中字段的名称。

  • 在mongo中使用regex时要小心用户输入!*

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