postman “status”:404 Sping Boot CRUD中的POST请求错误

guicsvcw  于 2023-01-20  发布在  Postman
关注(0)|答案(2)|浏览(302)

我开发了Sping Boot CRUD应用程序,连接的数据库是PostgreSQL,@GetMapping工作正常,GET请求可以检索到一个空的对象数组,但是在@PostMapping中,POST请求给出404错误。
📌Spring概述应用程序.java

package com.example.SpringRecap;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.autoconfigure.security.servlet.SecurityAutoConfiguration;
import org.springframework.web.bind.annotation.*;

import java.util.List;

@RestController
@SpringBootApplication(exclude = SecurityAutoConfiguration.class)
//@RequestMapping("api/v1/customers")
//@EnableWebMvc
@RequestMapping(name = "api/v1/customers" ,method = RequestMethod.POST)

public class SpringRecapApplication {
    //dependency injection
    private static  CustomerRepository customerRepository;

    public SpringRecapApplication(CustomerRepository customerRepository) {
        this.customerRepository = customerRepository;
    }

    public static void main(String[] args) {
        SpringApplication.run(SpringRecapApplication.class, args);
    }

    @GetMapping
    public List<Customer> getCustomer() {

        return customerRepository.findAll();

    }

    record NewCustomerRequest(
            String name,
            String email,
            Integer age
    ) {
        @PostMapping
        public void addCustomer(@RequestBody NewCustomerRequest newCustomerRequest) {
            Customer customer = new Customer();
            customer.setAge(newCustomerRequest.age());
            customer.setName(newCustomerRequest.name());
            customer.setEmail(newCustomerRequest.email());
            customerRepository.save(customer);
        }
    }

}

customerRepository.save(customer);不允许使依赖注入最终化。(private static CustomerRepository customerRepository;)。IDEA建议使其静态化。但它不起作用。当我使用@RequestMapping("api/v1/customers")时,收到了一个405错误。然后我通过以下操作修复了这个问题,

@RequestMapping(name = "api/v1/customers" ,method = RequestMethod.POST)

📌客户存储库.java

package com.example.SpringRecap;

import org.springframework.data.jpa.repository.JpaRepository;

public interface CustomerRepository extends JpaRepository<Customer,Integer> {
}

📌客户.java

package com.example.SpringRecap;

import jakarta.persistence.*;

import java.util.Objects;

@Entity
public class Customer {
    @Id
    @SequenceGenerator(
            name = "customer_id_sequence",
            sequenceName = "customer_id_sequence",
            allocationSize = 1

    )
    @GeneratedValue(
            strategy = GenerationType.SEQUENCE,
            generator = "customer_id_sequence"

    )
    private Integer id;
    private String name;
    private String email;
    private Integer age;

    public Customer(Integer id, String name, String email, Integer age) {
        this.id = id;
        this.name = name;
        this.email = email;
        this.age = age;
    }

    public Customer() {

    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(Integer age) {
        this.age = age;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;
        Customer customer = (Customer) o;
        return Objects.equals(id, customer.id) && Objects.equals(name, customer.name) && Objects.equals(email, customer.email) && Objects.equals(age, customer.age);
    }

    @Override
    public int hashCode() {
        return Objects.hash(id, name, email, age);
    }

    @Override
    public String toString() {
        return "Customer{" +
                "id=" + id +
                ", name='" + name + '\'' +
                ", email='" + email + '\'' +
                ", age=" + age +
                '}';
    }
}

Postman :

如果需要更多信息才能获得解决方案,请发表评论。

06odsfpq

06odsfpq1#

您的代码问题在于您将POST端点指定为DTO的一部分,而不是控制器的一部分。由于您的DTO不是Spring托管bean,Spring不会将URLMap到您的端点。无论如何,您应该将端点移到一个单独的类中。示例:

@RestController
@RequestMapping("api/v1/customers")
public class CustomerController {

    private final CustomerRepository customerRepository;

    public SpringRecapApplication(CustomerRepository customerRepository) {
        this.customerRepository = customerRepository;
    }

    @GetMapping
    public List<Customer> getCustomer() {
        return customerRepository.findAll();
    }
    
    @PostMapping
    public void addCustomer(@RequestBody NewCustomerRequest newCustomerRequest) {
        Customer customer = new Customer();
        customer.setAge(newCustomerRequest.age());
        customer.setName(newCustomerRequest.name());
        customer.setEmail(newCustomerRequest.email());
        customerRepository.save(customer);
    }

    // Helper classes

    record NewCustomerRequest(String name, String email, Integer age) { }

}

最好将DTO也移到一个单独的类中。我建议将DTO放在dto包中,将控制器放在controller包中。
两个附注:你不应该通过你的API暴露你的实体。你应该使用DTO来处理传入和传出的数据。看看lombokmapstruct,它们让这变得非常容易。

nwwlzxa7

nwwlzxa72#

试试这个@RequestMapping("api/v1/customers")//@EnableWebMvc //@RequestMapping(name = "api/v1/customers" ,method = RequestMethod.POST)

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