首先从App.xaml中移除StartupUri属性，然后使用以下命令：

protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);

        bool doShutDown = ...;

        if (doShutDown)
        {
            Shutdown(1);
            return;
        }
        else
        {
            this.StartupUri = new Uri("Window1.xaml", UriKind.Relative);
        }
    }

如果从具有MainWindow的应用程序的app.xaml中移除StartupUri，则需要确保在OnStartup方法中进行以下调用，否则应用程序将不会在MainWindow关闭时终止。

this.ShutdownMode = System.Windows.ShutdownMode.OnMainWindowClose;

@Frank Schwieterman，这些东西可能会帮助您解决控制台窗口问题。

为了避免设置StartupUri和ShutdownMode属性，我做了一点不同的操作。首先编辑App.xaml文件，并将StartupUri替换为Startup：

<Application x:Class="Menu.App"
         xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
         xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
         xmlns:local="clr-namespace:Menu"
         Startup="Application_Startup">
    <Application.Resources>
    </Application.Resources>
</Application>

然后将Application_Startup与OnExit沿着添加到代码中：

public partial class App : Application
{
    private volatile static Mutex s_mutex;

    private void Application_Startup(object sender, StartupEventArgs e)
    {
        s_mutex = new Mutex(true, @"Global\MenuMutex", out bool grantedOwnership);

        if (!grantedOwnership)
        {
            MessageBox.Show($"Another instance is already running!", "Error", MessageBoxButton.OK, MessageBoxImage.Exclamation);
            Current.Shutdown();
        }
        else
            new MainWindow().Show();
    }

    protected override void OnExit(ExitEventArgs e)
    {
        s_mutex?.ReleaseMutex();
        s_mutex?.Dispose();
        s_mutex = null;
        base.OnExit(e);
    }

写入应用程序启动：

private void Application_Startup(object sender, StartupEventArgs e)  
{  
    ...
    if (!condition)  
    {  
        e.GetType()  
          .GetProperty("PerformDefaultAction", BindingFlags.Instance | BindingFlags.NonPublic)  
          .SetValue(e, false);  
        Shutdown();  
        return;  
    }  
    ...
}