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(31个答案)
What is destructuring assignment and its uses?(3个答案)
昨天关门了。
我的老师让我创建一个函数来删除每个对象内部的属性'密码'使用解构方法,但我认为他是在愚弄我,因为我还没有找到这样做的方法。
const test = [
{
email: "samu@kenzie.com",
endereco: { rua: "Rua Quitino", bairro: "Nações", zipCode: "78120-000"} ,
id: 1,
idade: 26,
nome: "Samuel Persuhn",
password: "51686aaasd2",
stacks: [ "JavaScript", "PostgreSQL", "Node.js" ]
},
{
email: "patrick@kenzie.com",
endereco: { rua: "Avenida São Paulo", bairro: "Centro", zipCode: "45687-000"},
id: 2,
idade: 22,
nome: "Patrick Nekel",
password: "supersenha123548",
stacks: [ "JavaScript", "MongoDB", "Python" ]
},
{
email: "samueleao@kenzie.com",
endereco: { rua: "Avenida Brasil", bairro: "Centro", zipCode: "4587-000"},
id: 3,
idade: 28,
nome: "Samuel Leão",
password: "hash*asdasda7788",
stacks: [ "HTML5", "CSS3", "React.js" ]
},
{
email: "danrley@kenzie.com",
endereco: { rua: "Rua do videomaker", bairro: "Hollywood", zipCode: "44744-000"},
id: 4,
idade: 30,
nome: "Danrley",
password: "889977",
stacks: [ "VideoMaker", "Effects", "Roteirista" ]
}
]
我尝试在每个对象内部使用解构,就好像每个参数是一个数组一样,但没有成功
3条答案
按热度按时间1tuwyuhd1#
最简单的解决方案是对数据执行
map
,返回一个新的对象数组,为每个对象destructure输入密码,并使用rest parameter syntax将所有其他对象属性赋给另一个对象,然后返回该对象。syqv5f0l2#
你将不再需要到remove或删除作为remove任何项目从列表将mutate.
1l5u6lss3#
你可以循环数组,析构每个数组的对象,只得到你需要的属性: