我有一个父进程在调用它的子进程，我把import pdb; pdb.set_trace()放到了子进程的代码中。
当我用python -m pdb parent.py启动父进程时，它被冻结了。调试器不响应我键入的任何命令。但是当我点击quit或continue时，它确实退出代码。
它看起来像pdb工作，但不产生任何输出。

$ python -m pdb parent.py
n -m pdb parent.py
> d:\scripts\parent.py(53)<module>()
-> '''
(Pdb) c

现在没有React了。
根据我在中断后得到的跟踪，它就在pdb.set_trace()调用后站在线路上。

>>>>>>>>>>>>>[2013.06.13-10:02:06] : accessed by child.py
Traceback (most recent call last):
File "child.py", line 40, in <module>
    sys.stderr = open(Definition_h.ErrLog, 'a', 0, encoding=Definition_h.utf8)
File "d:\scripts\Definition_h.py", line 863, in unicodeOpen
    def unicodeOpen(*args, **kwargs):
File "C:\Program Files (x86)\Python 2.5.4\lib\bdb.py", line 50, in trace_dispatch
    return self.dispatch_call(frame, arg)
File "C:\Program Files (x86)\Python 2.5.4\lib\bdb.py", line 79, in dispatch_call
    self.user_call(frame, arg)
File "C:\Program Files (x86)\Python 2.5.4\lib\pdb.py", line 134, in user_call
    self.interaction(frame, None)
File "C:\Program Files (x86)\Python 2.5.4\lib\pdb.py", line 187, in interaction
    self.cmdloop()
File "C:\Program Files (x86)\Python 2.5.4\lib\cmd.py", line 148, in cmdloop
    import readline
KeyboardInterrupt: !!!<unprintable KeyboardInterrupt object>
Error in sys.excepthook: