每当我点击输入按钮时,页面似乎要么显示
由于请求的内容类型不是'application/json',因此未尝试加载JSON数据。
或者很少,如果按下回车键,它会创建每个聊天的副本,并将其添加到div中
我已经删除了输入的关键事件,但由于一些奇怪的原因,输入功能仍然工作,我推测这是由于 Bootstrap ,但我不太确定。
<!DOCTYPE html>
<html lang="en" style="height: 500px">
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1" />
<title>Bootstrap</title>
<link href="https://cdn.jsdelivr.net/npm/bootstrap@5.3.0-alpha1/dist/css/bootstrap.min.css" rel="stylesheet" />
<link href="https://getbootstrap.com/docs/5.3/assets/css/docs.css" rel="stylesheet" />
<link href="https://fonts.googleapis.com/css?family=Lexend" rel="stylesheet" />
<link rel="stylesheet" href="{{ url_for('static', filename='css/stylesheet.css') }}">
<script src="https://cdn.jsdelivr.net/npm/bootstrap@5.3.0-alpha1/dist/js/bootstrap.bundle.min.js"></script>
<script src="https://cdn.tailwindcss.com"></script>
<script src="https://www.unpkg.com/spltjs@1.1.0"></script>
<script src="https://releases.jquery.com/git/jquery-git.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/typeit/5.0.2/typeit.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/animejs/3.2.1/anime.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
</head>
<body>
<nav class="navbar navbar-dark bg-dark">
<!-- Navbar content -->
<button type="button" class="btn btn-light" style="height:34px">click me</button>
<p style="color:white; font-family: Lexend;font-size: 15px;font-weight: 400;text-align: center;">AI for a healthier you</p>
<button type="button" class="btn btn-light" style="height:34px">click me</button>
</nav>
<br>
<center>
<div class="container" style="background-color:white ; border-radius: 20px;height:80%;-webkit-box-shadow: 10px 10px 79px -7px rgba(0,0,0,0.22);-moz-box-shadow: 10px 10px 79px -7px rgba(0,0,0,0.22);box-shadow: 10px 10px 79px -7px rgba(0,0,0,0.22);">
<p style="color:black" id="hello"></p>
<form method="post">
<div class="input-group mb-3">
<input type="text" class="form-control" placeholder="Type here...." aria-label="Recipient's username" aria-describedby="basic-addon2" name="userid" id="textinput">
<div class="input-group-append">
<button class="btn btn-outline-secondary" type="button" value="hello world" id="button">Submit</button>
</form>
</div>
</div>
</div>
</center>
<script>
document.getElementById("button").addEventListener("click", insertText);
// CREATES A DIV AND SENDS THE USERS TEXT
function insertText() {
let div = document.createElement("div");
let usertext = document.getElementById('textinput').value;
const usertext2 = 'Patient: ' + usertext;
let text = document.createTextNode(usertext2);
div.appendChild(text);
document.getElementById("hello").appendChild(div);
/////////////// submit JSON TO APP
var json_entry = usertext
fetch('/dashboard', {
method: 'POST',
body: JSON.stringify({
user_text: json_entry
}),
headers: {
'Content-Type': 'application/json'
}
});
let apiData;
fetch('/dashboard/api').then((response) => response.json()).then((data) => {
apiData = data;
let div = document.createElement('div');
let robot_reply = document.createTextNode(apiData);
div.appendChild(robot_reply);
document.getElementById("hello").appendChild(div);
});
////// ENTER BUTTON ////
///////////////////////
/////////////////////// allows the ability to hit the enter button
var input = document.getElementById("textinput");
}
</script>
</div>
</div>
</body>
</html>
1条答案
按热度按时间h79rfbju1#
当你点击enter时,它会触发
<form>
上的submit
事件,这将导致页面刷新。这基本上是浏览器功能中的一个。在<form>
标记内的字段中按下任何enter键都会导致表单提交。如果表单提交没有得到处理,它会尝试将表单POST
到当前URL。你需要把所有的东西都附加到
<form>
上的submit
事件,而不是按钮点击,你还需要调用e.preventDefault
来阻止浏览器默认的表单动作处理。此外,您需要在按钮上使用
type="submit"
,这样单击该按钮也会提交表单。使用表单提交事件对于可访问性来说也是更好的,它意味着用户可以在一个字段中按回车键或单击按钮,它将被处理。