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如何禁用商店的"输入报告"和"导出"按钮。如果商店正常运行，销售主管将输入数据或查看报告（按钮将启用）。此选择将根据已插入数据库的商店的状态（"运行"或"关闭"）进行。

下面是我的代码：

<table id="table-data2" class="table table-hover table-responsive">
  <thead class="table-primary">
    <tr class="paginate">
      <th scope="col">Sl No</th>
      <th scope="col">Name of the Shop</th>
      <th scope="col">Owner name</th>
      <th scope="col">Shop no</th>
      <th scope="col">Status</th>
      <th scope="col">Status</th>
      <th scope="col">Enter daily data</th>
      <th scope="col">Report</th>
      <th scope="col">Export report</th>
    </tr>
  </thead>
  <?php
  require 'dbconnect.php';
  if (isset($_POST['id'])) {

    $sql = "SELECT * FROM shopmaster WHERE shpid = '" . $_POST['id'] . "' ORDER BY shpname";
    $result = mysqli_query($conn, $sql) or die("SQL Query Failed.");

    if (mysqli_num_rows($result) > 0) {
      $i = 1;
      while ($row = mysqli_fetch_array($result)) {
  ?>
        <tbody id='myTable'>
          <tr>
            <td scope='row'><?php echo $i; ?></td>
            <td><?php echo $row['shpname']; ?></td>
            <td><?php echo $row['ownername']; ?></td>
            <td><?php echo $row1['shpno']; ?></td>
            <td><?php echo $row['status']; ?></td>
            <td>
              <a class="btn btn-warning" href="shopdetails.php?id=<?php echo $row['shpid']; ?> name=" insert">Enter</a>
            </td>
            <td>
              <a class="btn btn-info" href="shpfullRecord.php?id=<?php echo $row['shpid']; ?> name=" report">Report</a>
            </td>
            <td>
              <a class="btn btn-danger" href="createcsv.php?id=<?php echo $row['shpid']; ?> name=" report">Report</a>
            </td>
          </tr>
        <?php
        $i++;
      }
    } else {
      echo "No Record Found." 
?>
    <?php }
  }
    ?>
        </tbody>
</table>