我有一个URL,它通过http_build_query
函数变成查询字符串。
但是我有一个参数timestamp
,我不能修改它,×
变成了一个乘号x
。
是否有解决方法?
这是我的数组,它被传递给http_build_query
函数。
$parameters = array(
"transaction_id"=>uniqid("FF-"),
"timestamp"=> time(),
"order_total"=>$_SESSION['total_price'],
"order_total_with_vat"=>$_SESSION['total_price'] * 1.21,
"order_vat"=>"21",
"payment_method"=>"ideal",
"payment_status"=>"1",
"customer_name"=>$_SESSION['customer_data']['naam'],
"customer_address"=>$_SESSION['customer_data']['address'],
"customer_city"=>$_SESSION['customer_data']['city'],
"customer_zipcode"=>$_SESSION['customer_data']['zipcode'],
"customer_country"=>$_SESSION['customer_data']['country'],
"customer_email"=>$_SESSION['customer_data']['email'],
"customer_telephone"=>$_SESSION['customer_data']['telephone'],
);
url的输出:
http://somedomain/subdir/someapi/order?transaction_id=FF-58e2451c5aea9×tamp=1491223836&order_total=156695&order_total_with_vat=189600.95&order_vat=21&payment_method=ideal&payment_status=1&customer_name=t&customer_address=t&customer_city=t&customer_zipcode=t&customer_country=t&customer_email=t%40t&customer_telephone=t&product%5B0%5D=5&product%5B1%5D=5&product%5B2%5D=5&product%5B3%5D=5&product%5B4%5D=5&product%5B5%5D=5&product%5B6%5D=5
首选输出:
http://somedomain/subdir/someapi/order?transaction_id=FF-58e2451c5aea9×tamp=1491223836&order_total=156695&order_total_with_vat=189600.95&order_vat=21&payment_method=ideal&payment_status=1&customer_name=t&customer_address=t&customer_city=t&customer_zipcode=t&customer_country=t&customer_email=t%40t&customer_telephone=t&product%5B0%5D=5&product%5B1%5D=5&product%5B2%5D=5&product%5B3%5D=5&product%5B4%5D=5&product%5B5%5D=5&product%5B6%5D=5
http_build_query
函数:
case 'POST':
curl_setopt( $curlHandler, CURLOPT_POST, true );
$url .= '?' . http_build_query( $parameters );
break;
2条答案
按热度按时间o8x7eapl1#
目前它工作正常。问题是当您回显您的URL时,序列
×
会使您的浏览器将其替换为乘法符号x
。要回显它并在浏览器中显示正确的方式,请尝试以下操作:这将显示所需的URL。
ui7jx7zq2#
@新手说对了,他评论我的问题:
这只是浏览器中的一个显示问题,但您的curl数据会像您在首选输出中显示的那样,无需添加任何额外的内容,只需点击即可!-新手
当我检查apache access.log时,我可以看到发布的首选查询字符串。