let unique = [...new Set(data.map(i => JSON.stringify(i)))].map(i => JSON.parse(i));

这种方法强制执行一致的键顺序，并在每个对象上使用JSON.stringify来测试唯一性。

const data = [ { "name": "abc", age: "31", project: "Java" }, { "name": "abc", age: "31", project: "Java" }, { "name": "abc", age: "29", project: "Javascript" }, { "name": "abc", age: "31", project: "C++" }, { "name": "abc", age: "31", project: "Java" }, { "name": "abc", age: "31", project: "Java" }]

const result = [...new Set(data.map(i=>JSON.stringify(Object.fromEntries(
  Object.entries(i).sort(([a],[b])=>a.localeCompare(b))))
))].map(JSON.parse)

console.log(result)

根据您的数据，project属性包含动态值。因此，您可以使用Array.filter()方法在单行代码中过滤出重复的值。
现场演示**：**

const data = [ { "name": "abc", age: "31", project: "Java" }, { "name": "abc", age: "31", project: "Java" }, { "name": "abc", age: "29", project: "Javascript" }, { "name": "abc", age: "31", project: "C++" }, { "name": "abc", age: "31", project: "Java" }, { "name": "abc", age: "31", project: "Java" }];

const uniq = {};

var arrFiltered = data.filter(obj => !uniq[obj.project] && (uniq[obj.project] = true));

console.log(arrFiltered);