我有一个注册客户端的函数。该函数负责创建用户、用户公司以及添加一些关于用户的 meta数据。然而，该函数的脆弱之处在于，如果其中一个请求失败，用户就会被卡住，无法再次注册。有人告诉我，可以使用事务或批处理来解决这个问题。我研究过writeBatch（）和批处理，但您似乎需要引用要更新的文档。然而，在我的情况下，我正在创建新文档-我如何将其重构为事务/批处理？到目前为止，我所拥有的是：

const registerUser = async (user: RegisterUserData) => {
    try {
      const batch = writeBatch(db);

      const test = await runTransaction(db, async (transaction) => {
        const userDoc = await createUserWithEmailAndPassword(auth, user.email, user.password);
        const userId = userDoc.user.uid;

        const companyRef = batch.set(doc(db, 'companies'), {
          title: user.companyName,
          userCount: 1
        });

        let isAdmin = false;
        if (await setUserAsAdmin(userId)) {
          isAdmin = true;
        }

        batch.set(doc(db, 'users'), {
          email: user.email,
          userId: userId,
          firstName: user.firstName,
          lastName: user.lastName,
          isAdmin: isAdmin,
          role: isAdmin ? 'admin' : 'coach',
          clientCount: 0,
          // companyId: companyRef.id
        });
        await batch.commit();
      });
      console.log('test', test)
    } catch (e) {
      console.log('error', e);
      throw new Error('cant register user: ' + e);
    }
  };

重构之前的原始函数如下所示（并且正在工作）：

const registerUser = async (user: RegisterUserData) => {
    try {
      const createUser = await createUserWithEmailAndPassword(auth, user.email, user.password);
      const createdCompany = await createUserCompany({
        title: user.companyName,
        userCount: 1
      });
      let isAdmin = false;
      const adminSet = await setUserAsAdmin(createUser.user.uid);
      if (adminSet) {
        isAdmin = true;
      }
      await createUserMetaData({
        email: user.email,
        userId: createUser.user.uid,
        firstName: user.firstName,
        lastName: user.lastName,
        isAdmin: isAdmin,
        role: isAdmin ? 'admin' : 'coach',
        clientCount: 0,
        companyId: createdCompany.id
      });
      return createUser;
    } catch (e) {
      throw new Error('cant register user' + e);
    }
  };