看起来你可能找错地方了。你正在发布，但是在请求中寻找数据。GET：
尝试在“request.post”和“request.files”中查找QueryDict ...
http://docs.djangoproject.com/en/1.6/ref/request-response/#django.http.HttpRequest.FILES

我有同样的问题与MultipartEntity请求。我需要上传图像到服务器。所以我做了HttpURLConnection类的MultipartEntity请求。我把我的代码在这里，认为它可以为您有用。你需要设置URL路径和文件路径。为此使用方法把。

public class UploadImage
implements Runnable{

private static String delimiter = "--";
private static String boundary = "SwA" + Long.toString(System.currentTimeMillis()) + "SwA";
private static int bytesRead;
private static int bytesAvailable;
private static int bufferSize;
private static byte[] buffer;
private static int maxBufferSize = 1 * 1024 * 1024;

private String URL;
private String file;

@Override
public void run()
{
    HttpURLConnection conn = null;
    String response = null;
    try {

        URL url = new URL(URL);
        conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setDoInput(true);
        conn.setUseCaches(false);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Connection", "Keep-Alive");
        conn.setRequestProperty("Content-type", "multipart/form-data; boundary=" + boundary);
        conn.setRequestProperty("USER-AUTH", UserPreferences.getToken());
        conn.connect();
        //

        DataOutputStream dos = new DataOutputStream(conn.getOutputStream());
        dos.writeBytes((delimiter + boundary + "\r\n"));
        dos.writeBytes("Content-Disposition: form-data; name=\"" + "image" + "\"; filename=\"" + file + "\"\r\n");
        dos.writeBytes("Content-Type: mimetype\r\n");// Content-Type:
                                                     // text/plain
        dos.writeBytes("Content-Transfer-Encoding: binary\r\n\r\n");

        // create a buffer of maximum size
        FileInputStream fileInputStream = new FileInputStream(new File(file));
        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        buffer = new byte[bufferSize];
        // read file and write it into form...
        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        while (bytesRead > 0) {
            dos.write(buffer, 0, bufferSize);

            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        }

        dos.writeBytes("\r\n");
        dos.writeBytes(delimiter + boundary + delimiter + "\r\n");
        fileInputStream.close();
        dos.flush();
        dos.close();
        int responseCode = conn.getResponseCode();

        if (responseCode != 200) {
            throw new Exception(String.format("Received the response code %d from the URL %s", responseCode, url));
        }

        InputStream is = conn.getInputStream();
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        byte[] bytes = new byte[1024];
        int bytesRead;
        while ((bytesRead = is.read(bytes)) != -1) {
            baos.write(bytes, 0, bytesRead);
        }
        byte[] bytesReceived = baos.toByteArray();
        baos.close();

        is.close();
        response = new String(bytesReceived);

    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        if (conn != null) {
            conn.disconnect();
        }
    }
}

public void put(String targetURL, String file)
{
    this.URL = targetURL;
    this.file = file;
}}