我正在尝试在两个表之间做一个复杂的不相等连接。我受到了上一次useR2016(https://channel9.msdn.com/events/useR-international-R-User-conference/useR2016/Efficient-in-memory-non-equi-joins-using-datatable)演示的启发,它让我相信这将是一个适合data.table的任务。我的表1看起来像:
library(data.table)
sp <- c("SAB","SAB","SAB","SAB","EPN","EPN","BOP","BOP","BOP","BOP","BOP","PET","PET","PET")
dbh <- c(10,12,16,22,12,16,10,12,14,20,26,12,16,18)
dt1 <- data.table(sp,dbh)
dt1
sp dbh
1: SAB 10
2: SAB 12
3: SAB 16
4: SAB 22
5: EPN 12
6: EPN 16
7: BOP 10
8: BOP 12
9: BOP 14
10: BOP 20
11: BOP 26
12: PET 12
13: PET 16
14: PET 18
这是一个树木及其胸径的列表。我的第二个表(下面)给出了一个通用表,为每个树种提供了一个胸径范围,以划分大小级别或树木:
gr_sp <- c("RES","RES","RES","RES","RES","RES", "DEC", "DEC", "DEC", "DEC", "DEC", "DEC")
sp <- c("SAB","SAB", "SAB", "EPN", "EPN", "EPN", "BOP", "BOP", "BOP", "PET", "PET", "PET")
dbh_min <- c(10, 16, 22, 10, 14, 20, 10, 18, 24, 10, 20, 26)
dbh_max <- c(14, 20, 30, 12, 18, 30, 16, 22, 30, 18, 24, 30)
dhb_clas <- c("s", "m", "l", "s", "m", "l", "s", "m", "l", "s", "m", "l")
dt2 <- data.table(gr_sp, sp, dbh_min, dbh_max, dhb_clas)
dt2
gr_sp sp dbh_min dbh_max dhb_clas
1: RES SAB 10 14 s
2: RES SAB 16 20 m
3: RES SAB 22 30 l
4: RES EPN 10 12 s
5: RES EPN 14 18 m
6: RES EPN 20 30 l
7: DEC BOP 10 16 s
8: DEC BOP 18 22 m
9: DEC BOP 24 30 l
10: DEC PET 10 18 s
11: DEC PET 20 24 m
12: DEC PET 26 30 l
我希望我的最终表是两个表按物种(“sp”字段)的连接,并且在由“DBH_MIN”和“DBH_MAX”声明的dhb范围内。
data.table(dt1, gr_sp = c("RES","RES","RES","RES","RES","RES","DEC","DEC","DEC","DEC","DEC","DEC","DEC","DEC"), dhb_clas = c("s","s","m","l","s","m","s","s","s","m","l","s","s","s"))
sp dbh gr_sp dhb_clas
1: SAB 10 RES s
2: SAB 12 RES s
3: SAB 16 RES m
4: SAB 22 RES l
5: EPN 12 RES s
6: EPN 16 RES m
7: BOP 10 DEC s
8: BOP 12 DEC s
9: BOP 14 DEC s
10: BOP 20 DEC m
11: BOP 26 DEC l
12: PET 12 DEC s
13: PET 16 DEC s
14: PET 18 DEC s
我试过这样的方法:
dt1[dt2, on=.(sp=sp, dbh>=dbh_min, dbh<=dbh_max)]
这样行太多了...
谢谢你的帮忙
3条答案
按热度按时间uelo1irk1#
所以我非常接近了。我有两个问题,第一个是Data.Table包(Data table error could not find function ".")的错误安装导致了一个模糊的错误。
修复后,我走近一个发现:
用一个坏的dbh列给了我想要的东西。将命令反转为:
仅使用一个无用的额外列修复了该问题。
dldeef672#
对于像这样的“between”连接,也可以使用
data.table::foverlaps
,它连接两个data.table
在重叠的范围上,而不是使用非相等连接。以同样的例子为例,下面的代码将产生所需的结果。
yacmzcpb3#
使用
join_by
,在dplyr 1.1.0
中可用。您也可以使用助手between
。输出