代码的问题在于for循环中的return语句只返回_cars数组中的第一个car对象并终止循环。要返回所有car，可以将car对象连接成一个字符串，并在循环后返回该字符串：

const carFactory = {
    _cars:[
        {
            make: 'default',
            model: 'default',
            year: 0,
        }
    ],

    get cars(){
        if(this._cars.length > 0 ){
            let allCars = '';
            for(let i = 0; i < this._cars.length; i++){
                allCars += `Car Make: ${this._cars[i].make} - Car Model: ${this._cars[i].model} Manufacture Year: ${this._cars[i].year}\n`;
            }
            return allCars;
        }else{
            return `Please add car details`;
        }
    },

    addCar(carMake, carModel, carYear){
        this._cars.push({
            make: carMake,
            model: carModel,
            year: carYear
        })
    }
}

carFactory.addCar('Toyota', 'Corolla', 2003);

console.log(carFactory.cars);

• • 输出：**

Car Make: default - Car Model: default Manufacture Year: 0
Car Make: Toyota - Car Model: Corolla Manufacture Year: 2003

在for中有一个return，它将在第一次迭代时退出循环：

for(let i = 0; i < this._cars.length; i++){
  return `Car Make: ${this._cars[i].make} - Car Model: ${this._cars[i].model} Manufacture Year: ${this._cars[i].year}`;
 }

如果你想返回一个数组，那么就返回一个数组。2 addCar方法需要有正确名字。

const carFactory = {
    _cars: [
        {
            make: 'default',
            model: 'default',
            year: 0,
        }
    ],

    get cars() {
        if (this._cars.length > 0) {
            let allCars = [];
            for (let i = 0; i < this._cars.length; i++) {
                let c = `Car Make: ${this._cars[i].make} - Car Model: ${this._cars[i].model} Manufacture Year: ${this._cars[i].year}`;
                allCars.push(c)
            }
            return allCars
        } else {
            return `Please add car details`;
        }
    },

    addCar(make, model, year) {
        this._cars.push({
            make,
            model,
            year
        })
    }
}

carFactory.addCar('Toyota', 'Corolla', 2003);
console.log(carFactory.cars);