MySQL子选择忽略条件

62lalag4  于 2023-02-03  发布在  Mysql
关注(0)|答案(2)|浏览(158)

这个查询运行良好,但是完全忽略了**AND members. active ='1 '**条件。
无论active是1还是0,它始终提供相同的结果。
你知道吗?

select amount, count(*) AS quantity
from
(
SELECT participations.member_number, COUNT(participations.member_number) AS amount
FROM participations
LEFT JOIN members
ON
participations.member_number=members.member_number
AND members.active='1'
GROUP BY participations.member_number
)
DT
group by amount
order by amount
kwvwclae

kwvwclae1#

这是另一种方法:

select amount, count(*) AS quantity
from
(
    SELECT participations.member_number, COUNT(participations.member_number) AS amount
    FROM participations
    LEFT JOIN members on participations.member_number=members.member_number 
    WHERE members.active='1'
    GROUP BY participations.member_number
)
DT
group by amount
order by amount;

说明:
使用WHERE:连接后。记录将在连接后进行筛选。
使用ON:联接前。联接前将筛选记录(来自右表)。
对于INNER JOIN,这些子句是等效的。

htrmnn0y

htrmnn0y2#

问题可能出在LEFT JOIN语句中的AND子句。您可以尝试将AND子句移到WHERE子句中,如下所示:

FROM participations
LEFT JOIN members ON participations.member_number=members.member_number
WHERE members.active='1'
GROUP BY participations.member_number, members.active
) DT
GROUP BY amount
ORDER BY amount

这样,AND子句将应用于从参与表和成员表中筛选出的数据,而不是应用于整个数据。

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