我试图从一个包含像素颜色值的数组创建一个HBITMAP。问题是当我试图创建一个24-bpp位图时，CreateDIBItmap使用的是BGR值而不是RGB值。
创建位图的代码如下所示：

image_size = 600 * 600 * 3;
 aimp_buffer = (char *)malloc(image_size * sizeof(char));
 for (counter = 0; counter < image_size;)
 {
     aimp_buffer[counter++] = 255;
     aimp_buffer[counter++] = 0;
     aimp_buffer[counter++] = 0;
 }

 ads_scrbuf->avo_buffer = (void *)aimp_buffer;
 ads_scrbuf->im_height = 600;
 ads_scrbuf->im_width = 600;
 ads_scrbuf->im_scanline = 600;

 memset(&info, 0, sizeof(info));
 memset(&info.bmiHeader, 0, sizeof(info.bmiHeader));
 info.bmiHeader.biBitCount = 24;
 info.bmiHeader.biHeight= -600;
 info.bmiHeader.biWidth= 600;
 info.bmiHeader.biSize = sizeof(info.bmiHeader);
 info.bmiHeader.biPlanes = 1;
 info.bmiHeader.biCompression = BI_RGB;

 memset(&header, 0, sizeof(BITMAPV5HEADER));
 header.bV5Width = 600;
 header.bV5Height = 600;
 header.bV5BitCount = 24;
 header.bV5Size = sizeof(BITMAPV5HEADER);
 header.bV5Planes = 1;
 header.bV5Compression = BI_RGB;

 *adsp_hBitmap = CreateDIBitmap(GetDC(ds_apiwindow), (BITMAPINFOHEADER *)&header, 
     CBM_INIT, (void *)ads_scrbuf->avo_buffer, &info, DIB_RGB_COLORS)

这应该为所有的图像创建一个红色的背景，但它是蓝色的。