如何在Typescript中声明空字典数组?

eanckbw9  于 2023-02-05  发布在  TypeScript
关注(0)|答案(1)|浏览(139)

我一直在学习Typescript,通过创建一个任务管理器应用程序与React和Redux。我试图发送我的状态到Redux作为一个字典数组,但问题是,我需要声明一个空的字典数组之前,我可以通过它发送我的状态。
下面是我的App.tsx文件:

import React, { FC, useState } from "react"
import { useSelector, useDispatch } from "react-redux"
import TodoList from "./Components/TodoList"
import NameTodo from "./Components/NameTodo"
import { RootState } from "./todoStore"
import { createTodoCard } from "./todoReducer"

interface TodoListTemplate {
  title: string,
  id: number,
}

const App: FC = () => {

  // Contains all the generated todo-lists
  const [generatedTodoList, setGeneratedTodoList] = useState<any[]>([]);

  const selector = useSelector((state: RootState) => { return state.todo });
  const dispatch = useDispatch();

  const generateTodoList = (): void => {
    // Sending this to the Redux state as an array of dictionaries
    const todoList: TodoListTemplate = {
      title: selector.todoCardName,
      id: Math.floor(Math.random() * 10000),
    }
    setGeneratedTodoList([...generatedTodoList, todoList]);
    // Reducer that would send todoList to the Redux state
    dispatch(createTodoCard(generatedTodoList));
  }

  return (
        ...
  )
}

export default App

下面是我的todoReducer.ts文件:

import { createAction, createReducer, PayloadAction } from '@reduxjs/toolkit'

export const update = createAction<any[]>('update')
export const toggleNaming = createAction<boolean>('toggleNaming')
export const addTodoName = createAction<string>('addTodoName')

//This is the reducer that would send the todoList to the array of dictionaries
export const createTodoCard = createAction<Record<string, number>[]>('createTodoCard')

export const todoReducer = createReducer(
    {
        todoList: [''],
        toggleNamingMenuState: false,
        todoCardName: '',
        // It should be sent here
        todoCard: [],
    },
    (builder) => {
        builder
        .addCase(update, (state, action: PayloadAction<any[]>) => {
            state.todoList = action.payload
        })

        .addCase(toggleNaming, (state, action: PayloadAction<boolean>) => {
            state.toggleNamingMenuState = action.payload
        })

        .addCase(addTodoName, (state, action: PayloadAction<string>) => {
            state.todoCardName = action.payload
        })

        .addCase(createTodoCard, (state, action: PayloadAction<Record<string, number>[]>) => {
            state.todoCard = action.payload
        })
    }
)

export default todoReducer

我试过使用Record<k, v>,但我不确定我是否正确使用它。
下面是显示的错误:

Type 'Record<string, number>[]' is not assignable to type 'never[]'.
  Type 'Record<string, number>' is not assignable to type 'never'.

感谢您提前回复:)

0ejtzxu1

0ejtzxu11#

声明数组时,需要指定它的类型。

{
    todoList: [''],
    toggleNamingMenuState: false,
    todoCardName: '',
    // It should be sent here
    todoCard: [] as Array<Record<string, number>>,
 }

要么用这种方法做,要么开足马力为它创建一个接口,或者为reducer初始化式指定整个对象的类型。例如:

{
  todoList: [''],
  toggleNamingMenuState: false,
  todoCardName: '',
  // It should be sent here
  todoCard: [],
} : {
  todoCard: Array<Record<string, number>>,
 ...
}

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