我想创建一个Django表单ChoiceField。选项将从外部数据库中查询,并且应该通过参数{company_id}进行过滤。如何传递此参数?
views.py
if request.method == 'GET':
company_id = 1
site_id = 3
return render(request, 'sites/new-column.html',
{
'company_id': company_id,
'site_id': site_id,
'form_newcolumn': NewColumn(company_id),
})
forms.py
class NewColumn(forms.Form):
def __init__(self, *args, **kwargs):
company_id = kwargs.pop('company_id')
super(NewColumn, self).__init__(args, kwargs)
self.company_id = company_id # Add it as an instance variable
engine = db.engine("Database")
connection = engine.raw_connection()
cursor = connection.cursor()
cursor.execute(f"SELECT * FROM table WHERE id = '{company_id}' ; ")
all_rows = cursor.fetchall()
choices = forms.ChoiceField(
choices=[(row[0], row[1]) for row in all_rows],
help_text='Make your Choice'
)
如何传递{company_id}只查询需要的选项?
1条答案
按热度按时间rjee0c151#
我在以下位置找到了适合我的解决方案:
Django Form ChoiceField set choices in View in Form initial
我在www.example.com中放置了select语句,并设置了“choices”和“initial”的形式views.py而没有在类定义中使用任何definit。