android.app.RemoteServiceException:错误的startForeground通知

w41d8nur 于 2023-02-06 发布在 Android

关注(0)|答案(2)|浏览(623)

我正在尝试启动前台服务如下：

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {

    NotificationChannel chan = new NotificationChannel(
            getApplicationContext().getPackageName(),
            "My Foreground Service",
            NotificationManager.IMPORTANCE_LOW);
    chan.setLightColor(Color.BLUE);
    chan.setLockscreenVisibility(Notification.VISIBILITY_SECRET);

    NotificationManager manager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
    assert manager != null;
    manager.createNotificationChannel(chan);

    NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder( 
            this, "MyChannelId");
    Notification notification = notificationBuilder.setOngoing(true)
            .setSmallIcon(R.mipmap.my_icon)
            .setContentTitle("App is running on foreground")
            .setPriority(NotificationManager.IMPORTANCE_LOW)
            .setCategory(Notification.CATEGORY_SERVICE)
            .setChannelId("MyChannelId")
            .build();

    startForeground(1, notification);
}

此解决方案适用于Android 8.0模拟器。但我在Android 8.1，9.0和10.0模拟器上收到以下错误。

android.app.RemoteServiceException: Bad notification for startForeground: java.lang.RuntimeException: invalid channel for service notification: Notification(channel=MyChannelId pri=2 contentView=null vibrate=null sound=null defaults=0x0 flags=0x42 color=0x00000000 category=service vis=PRIVATE)
    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1945)
    at android.os.Handler.dispatchMessage(Handler.java:107)
    at android.os.Looper.loop(Looper.java:214)
    at android.app.ActivityThread.main(ActivityThread.java:7356)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:492)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:930)

PS：我尝试了非模拟器Android 9.0设备，没有得到这个错误.

android

来源：https://stackoverflow.com/questions/60529974/android-app-remoteserviceexception-bad-notification-for-startforeground

2条答案

按热度按时间

ljsrvy3e1#

发生问题的原因是您正在使用ID创建通道，但在其他ID中发送通知：

// Here, you are using the package name as channel ID
NotificationChannel chan = new NotificationChannel(
              getApplicationContext().getPackageName(), 
              "My Foreground Service",
              NotificationManager.IMPORTANCE_LOW);

// But here, you are sending notifications to "MyChannelId"
NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder( 
              this, "MyChannelId");

因此，我认为您只需将Channel ID更改为MyChannelID，如下所示：

NotificationChannel chan = new NotificationChannel(
              "MyChannelId",
              "My Foreground Service",
              NotificationManager.IMPORTANCE_LOW);

赞(0）回复(0）举报 2023-02-06

wswtfjt72#

Intent intent = new Intent(mContext, BaseActivity.class);
    intent.putExtra("fragment",curapp.getSection());
    intent.putExtra("appmodel",curapp);

    PendingIntent pendingIntent = PendingIntent.getActivity(this.getApplicationContext(), 1, intent, PendingIntent.FLAG_IMMUTABLE);

    mNotificationManager = new NotificationCompat.Builder(mContext,curapp.getId().toString());
    notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);

    mNotificationManager.setContentTitle(curapp.getName())
            .setContentText(mContext.getString(R.string.preparing_for_download))
            .setSmallIcon(R.drawable.ic_white_logo)
            .setProgress(100, 0, true)
            .setContentIntent(pendingIntent)
            .setOngoing(true)
            .setAutoCancel(true);

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)  {
        NotificationChannel channel =
                new NotificationChannel("NOTIFICATION_ID", "Downloading..",
                        NotificationManager.IMPORTANCE_DEFAULT);
        channel.setLightColor(Color.BLUE);
        channel.setLockscreenVisibility(Notification.VISIBILITY_PRIVATE);
        notificationManager.createNotificationChannel(channel);
        mNotificationManager.setChannelId("NOTIFICATION_ID");
    }

    Notification notification = mNotificationManager.build();
    startForeground(curapp.getId(), notification);

赞(0）回复(0）举报 2023-02-06

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android.app.RemoteServiceException:错误的startForeground通知

2条答案

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