我是汇编代码的新手，我正在尝试创建一个程序来添加2个两位数的值。但是结果是ASCII符号，我该怎么做才能显示十进制数？
.model small
.stack 100h
.data
digit1 db "enter first digit: $"
digit2 db 10,13,"enter 2nd digit: $"
number1 db 0
number2 db 0
first_number db 0
second_number db 0
result db 0
result_digit1 db 0
result_digit2 db 0
.code
main proc
;Prompt the user to enter the first number
mov ax,@data
mov ds,ax
lea dx, digit1
mov ah, 09h
int 21h
; Read the first digit of the first number into AL
mov ah, 01h`your text`
int 21h
sub al, 30h ; convert the ASCII code to its corresponding number
mov [number1], al
; Read the second digit of the first number into AL
mov ah, 01h
int 21h
sub al, 30h ; convert the ASCII code to its corresponding number
mov [number2], al
; Combine the digits to form the first number
mov al, [number1]
mov ah, [number2]
mov bx, 10
mul bx
add al, ah
mov [first_number], al
; Prompt the user to enter the second number
mov ah, 09h
mov dx, offset digit2
int 21h
; Read the first digit of the second number into AL
mov ah, 01h
int 21h
sub al, 30h ; convert the ASCII code to its corresponding number
mov [number1], al
; Read the second digit of the second number into AL
mov ah, 01h
int 21h
sub al, 30h ; convert the ASCII code to its corresponding number
mov [number2], al
; Combine the digits to form the second number
mov al, [number1]
mov ah, [number2]
mov bx, 10
mul bx
add al, ah
mov [second_number], al
; Add the two numbers
mov al, [first_number]
add al, [second_number]
mov [result], al
; Convert the result to ASCII code
add al, 30h
mov [result_digit1], al
mov al, [result]
div bx
mov [result_digit2], al
add al, 30h
; Print the result
mov ah, 02h
mov dl, [result_digit2]
int 21h
mov dl, [result_digit1]
int 21h
Main endp
End main例如，当输入11 + 22时，我期望的结果是33，但我得到的答案是ASCII符号而不是整数。我如何得到整数而不是ASCII符号
1条答案
按热度按时间qrjkbowd1#
请先检查输入
使用
mul bx，您将执行字长乘法，即将AX乘以BX。您需要使用字节大小乘法将最高有效位乘以10，然后将最低有效位加到它上面：如何输出高达99的结果
当输入11 + 22时我期望的结果是33，但我得到的答案是ASCII符号而不是整数。
您的转换代码添加30 h值太早！
第一步需要使用字节大小的除以10来分解 result 中的值：
下一步将这些数字转换为文本字符：
最后一步打印数字：