ios 在Swift中从字符串中删除“\”(反斜杠)

egdjgwm8 于 2023-02-10 发布在 iOS

关注(0)|答案(4)|浏览(414)

下面的代码：

let refreshedToken = FIRInstanceID.instanceID().token()

var encriptat3: String = "ope=sql&para=UPDATE xw_usuarios SET IDFIREBASE = '" + refreshedToken! + "' where USUARIO = '" + self.usuari + "'"
encriptat3 = encriptat3.stringByReplacingOccurrencesOfString("\\", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil)

字符串的最终值是：

"ope=sql&para=UPDATE xw_usuarios SET IDFIREBASE = \'XXXXXXX\' where USUARIO = \'99997\'"

我的要求是：我怎样才能从我的结束值中删除""并正确地构建我的网址？
我现在用的是Swift 2.3谢谢。

ios

来源：https://stackoverflow.com/questions/42957460/remove-backslash-from-string-in-swift

4条答案

按热度按时间

tag5nh1u1#

雨燕3号

let string1 = "ios\\programmer"
let string2 = string1.replacingOccurrences(of: "\\", with: "")
print("string2 --%@",string2);

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roqulrg32#

Swift 5.7+：

let value = "Some \\value with \\backslashes."
value.replacing("\\", with: "") // Some value with backslashes.

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np8igboo3#

let aString = "ope=sql&para=UPDATE xw_usuarios SET IDFIREBASE = \'XXXXXXX\' where USUARIO = \'99997\'"
let newString = aString.replacingOccurrences(of: "\\", with: "")

- 编辑：**

你用的是哪个版本的Xcode？你导入了Fondation吗？

let aString = "ope=sql&para=UPDATE xw_usuarios SET IDFIREBASE = \'XXXXXXX\' where USUARIO = \'99997\'"

let newString = (string as NSString).stringByReplacingOccurrencesOfString("\\", withString: "")

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bvuwiixz4#

var val = your string

val = val.replacingOccurrences(of: "your replace string here(like \,)", with: "")

赞(0）回复(0）举报 2023-02-10

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ios 在Swift中从字符串中删除“\”(反斜杠)

4条答案

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