Simple Spring应用程序返回路径错误

qmb5sa22 于 2023-02-11 发布在 Spring

关注(0)|答案(5)|浏览(114)

我创建了一个简单的Spring应用程序，在“/a”处有一个路由，但是当我尝试访问该路由时，我得到了一个错误。日志显示正在Map该路由，所以我不确定是什么导致了这个错误。日志中没有错误消息输出。
HomeController.java

package com.12345;

import org.apache.log4j.Logger;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;

@Controller
public class HomeController {

  static Logger log = Logger.getLogger(HomeController.class.getName());

    @RequestMapping("/a")
    public String home() {
    log.debug("a route reached");
        return "Home";
    }
}

Application.java

package com.12345.config;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.properties.EnableConfigurationProperties;
import org.springframework.context.annotation.ComponentScan;

@ComponentScan(basePackages="com.12345")
@EnableConfigurationProperties
@EnableAutoConfiguration
public class Application {

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
}

堆栈跟踪和输出

2016-11-22 10:36:40.512  INFO 644 --- [           main] s.w.s.m.m.a.RequestMappingHandlerAdapter : Looking for @ControllerAdvice: org.springframework.boot.context.embedded.AnnotationConfigEmbeddedWebApplicationContext@59fd97a8: startup date [Tue Nov 22 10:36:35 PST 2016]; root of context hierarchy
2016-11-22 10:36:40.615  INFO 644 --- [           main] s.w.s.m.m.a.RequestMappingHandlerMapping : Mapped "{[/a]}" onto public java.lang.String com.12345.HomeController.home()
2016-11-22 10:36:40.620  INFO 644 --- [           main] s.w.s.m.m.a.RequestMappingHandlerMapping : Mapped "{[/error]}" onto public org.springframework.http.ResponseEntity<java.util.Map<java.lang.String, java.lang.Object>> org.springframework.boot.autoconfigure.web.BasicErrorController.error(javax.servlet.http.HttpServletRequest)
2016-11-22 10:36:40.620  INFO 644 --- [           main] s.w.s.m.m.a.RequestMappingHandlerMapping : Mapped "{[/error],produces=[text/html]}" onto public org.springframework.web.servlet.ModelAndView org.springframework.boot.autoconfigure.web.BasicErrorController.errorHtml(javax.servlet.http.HttpServletRequest,javax.servlet.http.HttpServletResponse)
2016-11-22 10:36:40.665  INFO 644 --- [           main] o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapped URL path [/webjars/**] onto handler of type [class org.springframework.web.servlet.resource.ResourceHttpRequestHandler]
2016-11-22 10:36:40.665  INFO 644 --- [           main] o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapped URL path [/**] onto handler of type [class org.springframework.web.servlet.resource.ResourceHttpRequestHandler]
2016-11-22 10:36:40.717  INFO 644 --- [           main] o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapped URL path [/**/favicon.ico] onto handler of type [class org.springframework.web.servlet.resource.ResourceHttpRequestHandler]
2016-11-22 10:36:41.045  INFO 644 --- [           main] o.s.j.e.a.AnnotationMBeanExporter        : Registering beans for JMX exposure on startup
2016-11-22 10:36:41.137  INFO 644 --- [           main] s.b.c.e.t.TomcatEmbeddedServletContainer : Tomcat started on port(s): 8085 (http)
2016-11-22 10:36:41.144  INFO 644 --- [           main] com.12345.config.Application     : Started Application in 5.751 seconds (JVM running for 6.18)
2016-11-22 10:36:48.217  INFO 644 --- [nio-8085-exec-1] o.a.c.c.C.[Tomcat].[localhost].[/]       : Initializing Spring FrameworkServlet 'dispatcherServlet'
2016-11-22 10:36:48.217  INFO 644 --- [nio-8085-exec-1] o.s.web.servlet.DispatcherServlet        : FrameworkServlet 'dispatcherServlet': initialization started
2016-11-22 10:36:48.242  INFO 644 --- [nio-8085-exec-1] o.s.web.servlet.DispatcherServlet        : FrameworkServlet 'dispatcherServlet': initialization completed in 25 ms

===============
localhost:8085/a
Whitelabel Error Page

This application has no explicit mapping for /error, so you are seeing this as a fallback.

Tue Nov 22 10:47:39 PST 2016
There was an unexpected error (type=Not Found, status=404).

No message available

spring

来源：https://stackoverflow.com/questions/40749909/simple-spring-application-returning-error-for-route

5条答案

按热度按时间

nnsrf1az1#

我一直用这样的注解：

@RestController
@RequestMapping("")

关于控制器类，用于访问控制器并始终工作.
不如你试试：

package com.12345;

import org.apache.log4j.Logger;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;

@RestController
@RequestMapping("")
public class HomeController {

  static Logger log = Logger.getLogger(HomeController.class.getName());

    @RequestMapping("/a")
    public String home() {
    log.debug("a route reached");
        return "Home";
    }
}

然后在应用程序中，我有：

@SpringBootApplication

这应该能说明问题：

package com.12345.config;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.properties.EnableConfigurationProperties;
import org.springframework.context.annotation.ComponentScan;

import org.springframework.boot.autoconfigure.SpringBootApplication;

@ComponentScan(basePackages="com.12345")
@EnableConfigurationProperties
@EnableAutoConfiguration
@SpringBootApplication
public class Application {

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
}

赞(0）回复(0）举报 2023-02-11

zvokhttg2#

将@ResponseBody添加到home()应该可以解决这个问题，如果没有它，返回“Home”意味着响应静态文件Home。
或者，将@Controller更改为@RestController也可以。@RestController等于@Controller + @ResponseBody。

赞(0）回复(0）举报 2023-02-11

oxalkeyp3#

此处：

@RequestMapping("/a")
public String home() {
log.debug("a route reached");
    return "Home";
}

这里返回一个名为"Home"的视图，所以必须有一个Home.ext，其中ext是用于视图解析器的后缀扩展名。
如果添加@ResponseBody，则返回String "Home"作为响应的内容，这是完全不同的。

赞(0）回复(0）举报 2023-02-11

wgxvkvu94#

使用您提供的代码，请求实际上被接收。如果您没有配置您的日志记录器从调试类别实际记录，您的日志语句可能已经消失。
这里的错误是home（）方法的返回值。它将导致Spring使用您的视图解析器，或者如果您没有配置视图解析器，它将返回到默认值InternalResourceViewResolver。它将查找以下文件“src/main/resources/static/Home”并将其作为视图转发。由于在您的案例中没有找到它，Spring将尝试转发到未定义的错误页面。

赞(0）回复(0）举报 2023-02-11

mwngjboj5#

请使用servletPath.getRoutePath（）检查你的路由路径是否确实是http：//localhost：8080.然后继续你的Map（“/a”）.这将起作用.

赞(0）回复(0）举报 2023-02-11