shell 在Bash中连接字符串以在For循环中调用数组[duplicate]

eqfvzcg8 于 2023-02-13 发布在 Shell

关注(0)|答案(2)|浏览(97)

- 此问题在此处已有答案**：

How to iterate over an array using indirect reference?（7个答案）
3天前关闭。
我希望在bash中嵌套几个For循环，首先检查一个数组，然后基于该数组检查第二个数组。

#!/bin/sh

domArr=( "ABC" "DEF" "GHI" )
ABCarr=( "1" "2" "3" )
DEFarr=( "4" "5" "6" )
GHIarr=( "7" "8" "9" )

for domain in "${domArr[@]}"
do
    # This should be 'domain = "ABC"'
    for group in "${domain+arr[@]}"
    do
        # This should be 'group = "1"'
    done
done

shell

来源：https://stackoverflow.com/questions/75401883/concatenate-strings-in-bash-to-call-an-array-in-a-for-loop

2条答案

按热度按时间

zlhcx6iw1#

您可以这样使用它：

domArr=( "ABC" "DEF" "GHI" )
ABCarr=( "1" "2" "3" )
DEFarr=( "4" "5" "6" )
GHIarr=( "7" "8" "9" )

for domain in "${domArr[@]}"
do
    echo "iterating array ${domain}arr ..."
    a="${domain}arr[@]"
    for group in "${!a}"
    do
        echo "$group"
    done
done

输出：

iterating array ABCarr ...
1
2
3
iterating array DEFarr ...
4
5
6
iterating array GHIarr ...
7
8
9

赞(0）回复(0）举报 2023-02-13

bqjvbblv2#

简而言之：

#!/bin/bash

dom=( "ABC" "DEF" "GHI" )
ABC=( "1" "2" "3" )
DEF=( "4" "5" "6" )
GHI=( "7" "8" "9" )

for ((i=0; i<${#dom[@]}; i++)); do
    # This should be 'domain = "ABC"' + "1"
    echo "${dom[i]} ${ABC[i]}"
done

输出

ABC 1
DEF 2
GHI 3

赞(0）回复(0）举报 2023-02-13

我来回答

shell 在Bash中连接字符串以在For循环中调用数组[duplicate]

2条答案

输出

相关问题

热门标签

最新问答