Django休息框架:使用电子邮件而不是用户名获取授权令牌

e5nszbig  于 2023-02-14  发布在  Go
关注(0)|答案(4)|浏览(119)

我正在做一个项目,为移动的设备启用djangorest框架认证,我使用默认的令牌认证从发送用户名和密码的post请求中获取用户令牌。

curl --data "username=username&password=password" http://127.0.0.1:8000/api/api-token-auth/

(api/api-token-auth/是使用获取验证令牌视图配置的URL)

urlpatterns = [
    url(r'^api/api-token-auth/', obtain_auth_token),
    url(r'^', include(router.urls)),
]

并且响应是用户令牌。

{"token":"c8a8777aca969ea3a164967ec3bb341a3495d234"}

我需要获得用户令牌授权使用电子邮件密码后,而不是用户名密码,或两者兼而有之。我正在阅读自定义身份验证的文档http://www.django-rest-framework.org/api-guide/authentication/#custom-authentication...但真的,不是很清楚我。这对我很有帮助...谢谢:)。

zzwlnbp8

zzwlnbp81#

好了,我找到了一种方法,可以使用电子邮件或用户名获取auth令牌......这是序列化程序:

class AuthCustomTokenSerializer(serializers.Serializer):
    email_or_username = serializers.CharField()
    password = serializers.CharField()

    def validate(self, attrs):
        email_or_username = attrs.get('email_or_username')
        password = attrs.get('password')

        if email_or_username and password:
            # Check if user sent email
            if validateEmail(email_or_username):
                user_request = get_object_or_404(
                    User,
                    email=email_or_username,
                )

                email_or_username = user_request.username

            user = authenticate(username=email_or_username, password=password)

            if user:
                if not user.is_active:
                    msg = _('User account is disabled.')
                    raise exceptions.ValidationError(msg)
            else:
                msg = _('Unable to log in with provided credentials.')
                raise exceptions.ValidationError(msg)
        else:
            msg = _('Must include "email or username" and "password"')
            raise exceptions.ValidationError(msg)

        attrs['user'] = user
        return attrs

在email_or_username字段中,用户可以发送电子邮件或用户名,使用函数validateEmail(),我们可以检查用户是否尝试使用电子邮件或用户名登录,然后,我们可以查询用户示例是否有效,并对其进行身份验证。
这就是风景。

class ObtainAuthToken(APIView):
    throttle_classes = ()
    permission_classes = ()
    parser_classes = (
        parsers.FormParser,
        parsers.MultiPartParser,
        parsers.JSONParser,
    )

    renderer_classes = (renderers.JSONRenderer,)

    def post(self, request):
        serializer = AuthCustomTokenSerializer(data=request.data)
        serializer.is_valid(raise_exception=True)
        user = serializer.validated_data['user']
        token, created = Token.objects.get_or_create(user=user)

        content = {
            'token': unicode(token.key),
        }

        return Response(content)

然后:

curl --data "email_or_username=emailorusername&password=password" http://127.0.0.1:8000/api/my-api-token-auth/.

准备好了

zyfwsgd6

zyfwsgd62#

将这些要求写入settings.py

ACCOUNT_AUTHENTICATION_METHOD = 'email'
ACCOUNT_EMAIL_REQUIRED = True
ACCOUNT_USERNAME_REQUIRED = False

要进行检查,请将此json格式请求发送到您的服务器:

{
    "username":"youremail@mail.domain",
    "password":"Pa$$w0rd"
}
58wvjzkj

58wvjzkj3#

更改库正在使用的默认序列化程序,例如在auth/serializers.py

from django.contrib.auth import authenticate
from django.utils.translation import gettext_lazy as _

from rest_framework import serializers

class MyAuthTokenSerializer(serializers.Serializer):
    email = serializers.EmailField(label=_("Email"))
    password = serializers.CharField(
        label=_("Password",),
        style={'input_type': 'password'},
        trim_whitespace=False
    )

    def validate(self, attrs):
        email = attrs.get('email')
        password = attrs.get('password')

        if email and password:
            user = authenticate(request=self.context.get('request'),
                                email=email, password=password)

            # The authenticate call simply returns None for is_active=False
            # users. (Assuming the default ModelBackend authentication
            # backend.)
            if not user:
                msg = _('Unable to log in with provided credentials.')
                raise serializers.ValidationError(msg, code='authorization')
        else:
            msg = _('Must include "email" and "password".')
            raise serializers.ValidationError(msg, code='authorization')

        attrs['user'] = user
        return attrs

覆盖视图,例如auth/ www.example.com中的视图views.py

from rest_framework.authtoken import views as auth_views
from rest_framework.compat import coreapi, coreschema
from rest_framework.schemas import ManualSchema

from .serializers import MyAuthTokenSerializer

class MyAuthToken(auth_views.ObtainAuthToken):
    serializer_class = MyAuthTokenSerializer
    if coreapi is not None and coreschema is not None:
        schema = ManualSchema(
            fields=[
                coreapi.Field(
                    name="email",
                    required=True,
                    location='form',
                    schema=coreschema.String(
                        title="Email",
                        description="Valid email for authentication",
                    ),
                ),
                coreapi.Field(
                    name="password",
                    required=True,
                    location='form',
                    schema=coreschema.String(
                        title="Password",
                        description="Valid password for authentication",
                    ),
                ),
            ],
            encoding="application/json",
        )

obtain_auth_token = MyAuthToken.as_view()

例如,在auth/ www.example.com中连接URLurls.py

from .views import obtain_auth_token
urlpatterns = [
    re_path(r'^api-token-auth/', obtain_auth_token),
]

你已经准备好了!!

bvk5enib

bvk5enib4#

有一种更干净的方法来获取用户令牌。
只需运行manage.py shell 程序
然后

from rest_framework.authtoken.models import Token
from django.contrib.auth.models import User
u = User.objects.get(username='admin')
token = Token.objects.create(user=u)
print token.key

相关问题