lstEmployees = []
lstNames = []
counter = 0
def export_employee():
for employee in lstEmployees:
with open("file.txt", "w") as output:
output.write(str(employee))
def search_uen():
uen = input("Enter employee UEN: ")
for employee in lstEmployees:
if uen == employee[1]:
print("-----------------" + employee[0] + "------------------------")
print("UEN: " + employee[1])
print("Phone: " + employee[2])
print("Email: " + employee[3])
print("Salary: £" + employee[4])
return employee
return -1
def edit_employee():
search = search_uen()
if search == -1:
print("Employee not found...")
else:
name = input("Enter the new name of the employee: ")
uen = input("Enter the new UEN of the employee: ")
phone = input("Enter the Phone number of the employee: ")
email = input("Enter the email of the employee: ")
salary = input("Enter the salary of the employee: ")
search[0] = name
search[1] = uen
search[2] = phone
search[3] = email
search[4] = salary
def add_employee():
global counter
while counter < 5:
print("----------------------------------------------------------\n")
print(" Number of employee ({0:d})" .format(counter))
print("----------------------------------------------------------\n")
name = input("enter employee name: ")
lstNames.insert(counter, name)
uen = input("enter employee UEN: ")
phone = input("enter employee phone number: ")
email = input("enter employee email: ")
salary = input("enter employee salary: ")
lstEmployees.append([name, uen, phone, email, salary])
if counter > 5:
break
else:
continue
def print_employee():
for employee in lstEmployees:
print("-----------------" + employee[0] + "------------------------")
print("UEN: " + employee[1])
print("Phone: " + employee[2])
print("Email: " + employee[3])
print("Salary: £" + employee[4])
def main():
while True:
print('-------------------------------------------\n')
print('Welcome to the Employee Management System -\n')
print('-------------------------------------------\n')
print('[1] Add An Employee: \n')
print('[2] View All Employees: \n')
print('[3] Search Employees By UEN: \n')
print('[4] Edit Employees Information: \n')
print('[5] Export Employee Records: \n')
print('[6] Exit \n')
user_option = input("Please select an option ")
if user_option == "1":
add_employee()
elif user_option == "2":
print('\n' * 3)
print_employee()
print('\n' * 3)
elif user_option == "3":
found = search_uen()
if found == -1:
print("Employee not found...")
elif user_option == "4":
edit_employee()
elif user_option == "5":
export_employee()
elif user_option == "6":
print("thank you for using the employee management system")
exit()
else:
print("Please select valid option...")
if __name__ == "__main__":
main()
当我运行代码,并试图添加员工到应用程序,它显示员工的数量仍然为零,然后我陷入了一个循环,我无法摆脱添加员工.(图像显示我的意思:https://imgur.com/a/oZeeeXk)
我不知道我在代码中做错了什么,也不知道如何修复它,任何帮助解决这个问题都是很好的,因为我不知道这个问题是什么。我想它与计数有关,但我不是100%。
1条答案
按热度按时间zengzsys1#
在试用您的程序时,雇员加法函数中的“while”循环似乎并不合适。
没有增加计数器的代码,因此永远不会跳出“while”循环。
通过对该函数进行快速重构,我能够添加雇员并递增计数器。
你可以给予一下,看看它是否符合你的项目的精神。