#include <iostream>

struct Data
{
    std::shared_ptr<char[]> m_name = nullptr;  // char* m_name = nullptr;

//    bool m_owner = false;

    Data() = default;

    Data(const char* name)
    {
        using std::copy;

        int size = strlen(name) + 1;
        m_name = std::make_unique<char[]>(size); // m_name = new char[size];
        copy(name, name + size, m_name.get());
//        m_owner = true;
    }

//    ~Data()
//    {
//        if (/*m_name &&*/ m_owner)
//            delete[] m_name;
//        m_name = nullptr;
//    }

    void print()
    {
        using std::cout, std::endl;

        if (!m_name)
            return;
        int size = strlen(m_name.get());
        for(int i = 0; i < size; ++i)
            cout << m_name[i];
        cout << endl;
    }
};

void shallow_copy(Data& dst, Data& src)
{
    dst.m_name = src.m_name;
}

void deep_copy(Data& dst, Data& src)
{
    using std::copy;

    int size = strlen(src.m_name.get())+1;
    dst.m_name = std::make_unique<char[]>(size); // dst.m_name = new char[size];
    copy(src.m_name.get(), src.m_name.get() + size, dst.m_name.get());
//    dst.m_owner = true;
}

int main()
{
    using std::cout, std::endl;

    cout << "starting..." << endl;

    auto data1 = new Data{"abc"};
    data1->print();

    auto data2 = new Data();
    data2->print();

//    shallow_copy(*data2, *data1);
    deep_copy(*data2, *data1);

//    delete data1;

    data2->print();

}

在上面尝试将char*替换为std::shared_ptr<char[]>时，我注意到使用copy会变得有点冗长，从

copy(src.m_name, src.m_name + size, dst.m_name);

到

copy(src.m_name.get(), src.m_name.get() + size, dst.m_name.get());

有没有比每次都输入.get()更好（更短）的方法？