这段代码可以帮助你按日、月和年排序：

import numpy as np
from datetime import datetime

all_periods = np.array(['01/01/2021', '01/01/2022', '02/01/2021', '02/01/2022', '03/01/2020', '03/01/2021', '03/01/2022', '04/01/2020', '04/01/2021', '04/01/2022', '05/01/2020', '05/01/2021', '06/01/2020', '06/01/2021', '07/01/2020', '07/01/2021', '08/01/2020', '08/01/2021', '09/01/2020', '09/01/2021', '10/01/2020', '10/01/2021', '11/01/2020', '11/01/2021', '12/01/2020', '12/01/2021'])

dates = [datetime.strptime(d, '%d/%m/%Y') for d in all_periods]

sorted_dates = np.sort(dates)

sorted_periods = np.array([d.strftime('%d/%m/%Y') for d in sorted_dates])

print(sorted_periods)

• • 结果：**

['03/01/2020' '04/01/2020' '05/01/2020' '06/01/2020' '07/01/2020'
 '08/01/2020' '09/01/2020' '10/01/2020' '11/01/2020' '12/01/2020'
 '01/01/2021' '02/01/2021' '03/01/2021' '04/01/2021' '05/01/2021'
 '06/01/2021' '07/01/2021' '08/01/2021' '09/01/2021' '10/01/2021'
 '11/01/2021' '12/01/2021' '01/01/2022' '02/01/2022' '03/01/2022'
 '04/01/2022']

您可以简单地定义一个排序键函数并对字符串进行排序，而无需任何其他库：

def func(x):
    x = x.split('/')
    return '.'.join(reversed(x))
    
all_periods = sorted(all_periods, key = func)

它给出了

['03/01/2020', '04/01/2020', '05/01/2020', '06/01/2020', '07/01/2020', '08/01/2020', '09/01/2020', '10/01/2020', '11/01/2020', '12/01/2020', '01/01/2021', '02/01/2021', '03/01/2021', '04/01/2021', '05/01/2021', '06/01/2021', '07/01/2021', '08/01/2021', '09/01/2021', '10/01/2021', '11/01/2021', '12/01/2021', '01/01/2022', '02/01/2022', '03/01/2022', '04/01/2022']

希望对你有用

import numpy as np
from datetime import datetime
a = np.array([
    '01/01/2021', '01/01/2022', '02/01/2021', '02/01/2022', '03/01/2020',
    '03/01/2021', '03/01/2022', '04/01/2020', '04/01/2021', '04/01/2022',
    '05/01/2020', '05/01/2021', '06/01/2020', '06/01/2021', '07/01/2020',
    '07/01/2021', '08/01/2020', '08/01/2021', '09/01/2020', '09/01/2021',
    '10/01/2020', '10/01/2021', '11/01/2020', '11/01/2021', '12/01/2020',
    '12/01/2021'
])
# sort by year, month and day
sorted(a, key=lambda x: datetime.strptime(x, '%d/%m/%Y'))

• • 输出：**

['03/01/2020', '04/01/2020', '05/01/2020', '06/01/2020', '07/01/2020', '08/01/2020', '09/01/2020', '10/01/2020', '11/01/2020', '12/01/2020', '01/01/2021', '02/01/2021', '03/01/2021', '04/01/2021', '05/01/2021', '06/01/2021', '07/01/2021', '08/01/2021', '09/01/2021', '10/01/2021', '11/01/2021', '12/01/2021', '01/01/2022', '02/01/2022', '03/01/2022', '04/01/2022']

我倾向于将它们转换为numpy datetime64对象并直接排序，类似于：

import numpy as np
from datetime import datetime
dates = np.array([
    '01/01/2021', '01/01/2022', '02/01/2021', '02/01/2022', '03/01/2020',  
    '03/01/2021', '03/01/2022', '04/01/2020', '04/01/2021', '04/01/2022', 
    '05/01/2020', '05/01/2021', '06/01/2020', '06/01/2021', '07/01/2020', 
    '07/01/2021', '08/01/2020', '08/01/2021', '09/01/2020', '09/01/2021', 
    '10/01/2020', '10/01/2021', '11/01/2020', '11/01/2021', '12/01/2020', 
    '12/01/2021'
])
conv_dates = np.array([
    np.datetime64(
        datetime.strptime(d, "%d/%m/%Y").strftime("%Y-%m-%d")
    ) for d in dates])
sorted_dates = np.sort(conv_dates)