我有密钥列表（我只给出4个作为示例。它可能是100- 1 k密钥）

['session_id','following_status','job_name','last_interaction']

现在，我得到输入json如下，

[
  {
    "updated_data": {
      "last_interaction": "2022-06-20 06:55:55.652434",
      "following_status": "not followed",
      "session_id": "abc1",
      "job_name": "blogger-following",
      "target": "ghjk",
      "liked": 21,
      "watched": 8,
      "commented": 0,
      "followed": false,
      "unfollowed": false,
      "scraped": false,
      "pm_sent": false
    }
  },
  {
    "updated_data": {
      "last_interaction": "2022-06-20 06:55:55.652434",
      "following_status": "followed",
      "session_id": "abc2",
      "job_name": "blogger-following",
      "target": "name2",
      "liked": 1,
      "watched": 7,
      "commented": 0,
      "followed": false,
      "unfollowed": false,
      "scraped": false,
      "pm_sent": false
    }
  },
  {
    "updated_data": {
      "last_interaction": "2022-06-20 06:55:55.652434",
      "following_status": "followed",
      "session_id": "abc3",
      "job_name": "blogger-following",
      "target": "name3",
      "liked": 67,
      "watched": 78,
      "commented": 0,
      "followed": false,
      "unfollowed": false,
      "scraped": false,
      "pm_sent": false
    }
  },
  {
    "updated_data": {
      "last_interaction": "2022-06-20 06:55:55.652434",
      "following_status": "followed",
      "session_id": "abc4",
      "job_name": "blogger-following",
      "target": "name4",
      "liked": 210,
      "watched": 77,
      "commented": 0,
      "followed": false,
      "unfollowed": false,
      "scraped": false,
      "pm_sent": false
    }
  },
  {
    "updated_data": {
      "last_interaction": "2022-06-20 06:55:55.652434",
      "following_status": "followed",
      "session_id": "abc5",
      "job_name": "blogger-following",
      "target": "name5",
      "liked": 21,
      "watched": 790,
      "commented": 0,
      "followed": false,
      "unfollowed": false,
      "scraped": false,
      "pm_sent": false
    }
  },
  {
    "updated_data": {
      "last_interaction": "2022-06-20 06:55:55.652434",
      "following_status": "not followed",
      "session_id": "abc6",
      "job_name": "blogger-following",
      "target": "name6",
      "liked": 81,
      "watched": 7,
      "commented": 0,
      "followed": false,
      "unfollowed": false,
      "scraped": false,
      "pm_sent": false
    }
  }
]

我需要迭代json，如果与上面列表中的键匹配，我需要获取这些键值并推送到新的json文件
我应该通过匹配键来创建JSON，如果不匹配，则忽略那些键值。
输出将是，

[
  {
    "last_interaction": "2022-06-20 06:55:55.652434",
    "following_status": "not followed",
    "session_id": "abc1",
    "job_name": "blogger-following"
    
  },
  {
    "last_interaction": "2022-06-20 06:55:55.652434",
    "following_status": "followed",
    "session_id": "abc2",
    "job_name": "blogger-following"
  },
  {
    "last_interaction": "2022-06-20 06:55:55.652434",
    "following_status": "followed",
    "session_id": "abc3",
    "job_name": "blogger-following"
  },
  {
    "last_interaction": "2022-06-20 06:55:55.652434",
    "following_status": "followed",
    "session_id": "abc4",
    "job_name": "blogger-following"
  },
  {
    "last_interaction": "2022-06-20 06:55:55.652434",
    "following_status": "followed",
    "session_id": "abc5",
    "job_name": "blogger-following"
  },
  {
    "last_interaction": "2022-06-20 06:55:55.652434",
    "following_status": "not followed",
    "session_id": "abc6",
    "job_name": "blogger-following"
  }
]

我所尝试的

import json
from datetime import datetime
from operator import itemgetter

with open("data.json", "r") as f_in:
    data = json.load(f_in)

items = ["session_id", "following_status", "job_name", "last_interaction"]

i = itemgetter(*items)
out = [dict(zip(items, v)) for v in enumerate(data[0]['updated_data'].items())]

我都试过了

[{k: msgs[0]['updated_data'][k] for k in items if k in enumerate(msgs[0]['updated_data'].items())}]

未工作
请告诉我怎样才能达到目标。