我正在尝试嵌套平面列表。我正在使用两个Realm对象数组,需要根据“inventory”数组中的值有条件地显示“ingredients”数组中的项目。
我想知道我是否有我的“返回语句”放置错误或我的逻辑是否是扭曲的。请告知。任何帮助将不胜感激。谢谢。
import * as React from 'react';
import {View, Text, FlatList} from "react-native";
import realm from '../schemas/InventoryDatabase';
export default class ViewInventory extends React.Component {
constructor(props) {
super(props);
this.state = {
FlatListInventoryItems: [],
};
this.state = {
FlatListIngredientItems: [],
};
var inventories = Object.values(realm.objects('Inventories'));
var ingredients = Object.values(realm.objects('Ingredients'));
this.state = {
FlatListInventoryItems: inventories,
};
this.state = {
FlatListIngredientItems: ingredients,
};
}
ListViewItemSeparator = () => {
return (
<View style={{ height: 0.5, width: '100%', backgroundColor: '#000' }} />
);
};
render() {
return (
<View>
<FlatList
data={this.state.FlatListInventoryItems}
ItemSeparatorComponent={this.ListViewItemSeparator}
keyExtractor={(item, index) => index.toString()}
renderItem={({ item }) => (
<View style={{ backgroundColor: 'white', padding: 20 }}>
<Text>Inventory ID: {item.recordID}</Text>
<Text>Name: {item.inventoryName}</Text>
<Text>Date: {item.date}</Text>
<FlatList
data={this.state.FlatListIngredientItems}
ItemSeparatorComponent={this.ListViewItemSeparator}
keyExtractor={(item2, index) => index.toString()}
renderItem={({ item2 }) => {
if (item2.inventoryID == item.recordID) {
return (
<View style={{ backgroundColor: 'gray', padding: 20 }}>
<Text>Ingredient ID: {item2.ingredientID}</Text>
<Text>Ingredient Type: {item2.ingredientType}</Text>
<Text>Ingredient: {item2.ingredient}</Text>
</View>
);
}
}}
/>
</View>
)}
/>
</View>
);
}
}
1条答案
按热度按时间bfhwhh0e1#
一切看起来都很好。
但是,
ScrollView
不应嵌套。请考虑使用map
而不是第二个FlatList
。