既然你知道每行需要7个字符，那么就用end=""打印每个键-值对来隐藏换行符，然后每7次迭代打印一个：

for i, (char, price) in enumerate(charPricing.items()):
    char_price = math.ceil(price * fontPricing[fontsize])
    # create desired format and print
    print(f"{char} {char_price:.0f}\t", end="") 

    if i % 7 == 6:
        print() # print newline

它提供了所需的输出：

A 44    B 79    C 60    D 56    E 46    F 50    G 65    
H 45    I 38    J 49    K 51    L 36    M 48    N 55    
O 56    P 53    Q 41    R 58    S 65    T 36    U 23    
V 49    W 46    X 48    Y 54    Z 52    a 63    b 55    
c 37    d 55    e 63    f 58    g 40    h 31    i 36    
j 50    k 51    l 36    m 32    n 58    o 50    p 55    
q 55    r 53    s 61    t 57    u 37    v 33    w 59    
x 53    y 54    z 39    ! 35    & 65    * 65    $ 65    
# 64    . 30    , 36    < 38    > 38    ? 45    @ 65

注意：因为没有指定fontPricing[fontsize]，所以我假设它是1

下面是一个可能的解决方案。注意，通过指定输出表中的列数，我们可以一次打印一个单元格，并计算相应键在char定价字典中的位置。

import math

char_price = {'A': 44.0, 'B': 79.0, 'C': 60.0, 'D': 56.0, 'E': 46.0, 'F': 50.0, 'G': 65.0, 'H': 45.0, 'I': 38.0, 'J': 49.0, 'K': 51.0, 'L': 36.0, 'M': 48.0, 'N': 55.0, 'O': 56.0, 'P': 53.0, 'Q': 41.0, 'R': 58.0, 'S': 65.0, 'T': 36.0, 'U': 23.0, 'V': 49.0, 'W': 46.0, 'X': 48.0, 'Y': 54.0, 'Z': 52.0, 'a': 63.0, 'b': 55.0, 'c': 37.0, 'd': 55.0, 'e': 63.0, 'f': 58.0, 'g': 40.0, 'h': 31.0, 'i': 36.0, 'j': 50.0, 'k': 51.0, 'l': 36.0, 'm': 32.0, 'n': 58.0, 'o': 50.0, 'p': 55.0, 'q': 55.0, 'r': 53.0, 's': 61.0, 't': 57.0, 'u': 37.0, 'v': 33.0, 'w': 59.0, 'x': 53.0, 'y': 54.0, 'z': 39.0, '!': 35.0, '&': 65.0, '*': 65.0, '$': 65.0, '#': 64.0, '.': 30.0, ',': 36.0, '<': 38.0, '>': 38.0, '?': 45.0, '@': 65.0}
font_price = {24: 1}

def showPricing(charPricing, fontPricing, num_col=7):
    fontsize = int (input("Enter font size: "))
    title = f'Pricing for font size {fontsize}pts'
    print (title)
    print('=' * len(title))
    keys = list(charPricing.keys())
    row = 0
    for row in range(math.ceil(len(charPricing) / num_col)):
        for col in range(num_col):
            k = keys[num_col * row + col]
            print(k, math.ceil(charPricing[k] * fontPricing.get(fontsize, 0)), end='\t')
        print()  # new line
    
showPricing(char_price, font_price)