在Pandas中使用groupby和resample时如何显示datetime对象?

jw5wzhpr  于 2023-02-27  发布在  其他
关注(0)|答案(2)|浏览(114)

我有以下数据。

import numpy as np
import pandas as pd
import random

df = pd.DataFrame({'DATE_TIME': pd.date_range('2022-11-01', '2022-11-06 23:00:00', freq='20min'),
                   'ID': [random.randrange(1, 20) for n in range(430)]})

df['VALUE1'] = [random.randrange(110, 140) for n in range(430)]
df['VALUE2'] = [random.randrange(50, 60) for n in range(430)]
df['VALUE3'] = [random.randrange(80, 100) for n in range(430)]
df['VALUE4'] = [random.randrange(30, 50) for n in range(430)]

df['MODEL'] = [random.randrange(1, 3) for n in range(430)]

df['SOLD'] = [random.randrange(0, 2) for n in range(430)]

df['INSPECTION'] = df['DATE_TIME'].dt.day

df['MODE'] = np.select([df['INSPECTION'] == 1, df['INSPECTION'].isin([2, 3])], ['A', 'B'], 'C')

df['TIME'] = df['DATE_TIME'].dt.time
# df['TIME'] = pd.to_timedelta(df['TIME'])
df['TIME'] = df['TIME'].astype('str')

# Create DAY Night columns only-------------------------------------------------------------------------
def cycle_day_period(dataframe: pd.DataFrame, midnight='00:00:00', start_of_morning='06:00:00',
                     start_of_afternoon='13:00:00',
                     start_of_evening='18:00:00', end_of_evening='23:00:00', start_of_night='24:00:00'):
    bins = [midnight, start_of_morning, start_of_afternoon, start_of_evening, end_of_evening, start_of_night]
    labels = ['Night', 'Morning', 'Morning', 'Night', 'Night']

    return pd.cut(
        pd.to_timedelta(dataframe),
        bins=list(map(pd.Timedelta, bins)),
        labels=labels, right=False, ordered=False
    )

df['CYCLE_PART'] = cycle_day_period(df['TIME'], '00:00:00', '06:00:00', '13:00:00', '18:00:00', '23:00:00', '24:00:00')

我使用下面的脚本根据条件对时间序列重新采样。

freq = {'Night': '30min', 'Morning': '15min'}
out = (df.groupby('CYCLE_PART')
         .apply(lambda g: g.resample(freq[g.name], on='DATE_TIME').mean())
         .reset_index()
       )

但是,当我打印它的输出时,DATE_TIMETIME都不可见。我该如何解决这个问题?

46qrfjad

46qrfjad1#

一种方法是先创建DatetimeIndex,因此可以省略on参数:

out = (df.set_index('DATE_TIME')
         .groupby('CYCLE_PART')
         .apply(lambda g: g.resample(freq[g.name]).mean())
         .reset_index())
mpbci0fu

mpbci0fu2#

你的思路是正确的。以下是你所做工作的最新进展:

out = (df.groupby(['CYCLE_PART', pd.Grouper(key='DATE_TIME', freq='1min'), 'TIME'], as_index=False)
       .apply(lambda g: g.resample(freq[g.name[0]], on='DATE_TIME').mean(numeric_only=True))
     )

out = out.reset_index()
out['TIME'] = out['DATE_TIME'].dt.time

其给出:

level_0           DATE_TIME    ID  VALUE1  VALUE2  VALUE3  VALUE4  MODEL  \
0          0 2022-11-01 06:00:00   6.0   110.0    56.0    92.0    40.0    2.0   
1          1 2022-11-01 06:15:00  19.0   132.0    55.0    82.0    37.0    2.0   
2          2 2022-11-01 06:30:00   9.0   130.0    50.0    87.0    31.0    2.0   
3          3 2022-11-01 07:00:00   5.0   118.0    52.0    95.0    31.0    1.0   
4          4 2022-11-01 07:15:00  17.0   125.0    56.0    81.0    48.0    1.0   
..       ...                 ...   ...     ...     ...     ...     ...    ...   
425      425 2022-11-06 21:30:00   7.0   132.0    58.0    94.0    39.0    1.0   
426      426 2022-11-06 22:00:00  12.0   126.0    53.0    87.0    41.0    1.0   
427      427 2022-11-06 22:00:00   8.0   129.0    52.0    96.0    34.0    2.0   
428      428 2022-11-06 22:30:00   9.0   114.0    50.0    98.0    45.0    1.0   
429      429 2022-11-06 23:00:00   7.0   110.0    50.0    96.0    35.0    2.0   

     SOLD  INSPECTION      TIME  
0     1.0         1.0  06:00:00  
1     0.0         1.0  06:15:00  
2     0.0         1.0  06:30:00  
3     1.0         1.0  07:00:00  
4     0.0         1.0  07:15:00  
..    ...         ...       ...  
425   1.0         6.0  21:30:00  
426   1.0         6.0  22:00:00  
427   1.0         6.0  22:00:00  
428   1.0         6.0  22:30:00  
429   0.0         6.0  23:00:00  

[430 rows x 11 columns]

相关问题