我试图得到一个没有根节点的列表输出。我将用一个更简单的想法来简化我的代码：

@JacksonXmlRootElement(localName = "my_company")
    public class Company {

     //Creating properties of Company class
     public String comName;
     public String comEmail;

     @JacksonXmlElementWrapper(useWrapping = false)
     public List<Parent> childs;

     // constructor
     Company(String comName, String comEmail, List<Parent> childs) {
        this.comName = comName;
        this.comEmail = comEmail;
        this.childs = childs;
     }

    @JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.WRAPPER_OBJECT)
    class Parent{

    }
    @JsonTypeName("my_child")
     class Child extends Parent{
      public String street;
      public String state;
      public String city;

      Child(String street, String state, String city){
         this.street = street;
         this.state = state;
         this.city = city;
     }
  }

这是我得到的结果：

<my_company>
       <comName>A</comName>
       <comEmail>ema</comEmail>
       <childs>
         <my_child>
           <street>a</street>
           <state>b</state>
          <city>c</city>
        </my_child>
       </childs>
       <childs>
        <my_child>
          <street>a</street>
          <state>b</state>
          <city>c</city>
        </my_child>
       </childs>
   </my_company>

我不想这样，我需要删除“查尔兹”标签，我想这样：

<my_company>
        <comName>A</comName>
        <comEmail>ema</comEmail>
          <my_child>
             <street>a</street>
             <state>b</state>
             <city>c</city>
          </my_child>
         <my_child>
            <street>a</street>
            <state>b</state>
            <city>c</city>
         </my_child>
    </my_company>

***@JacksonXmlElementWrapper（useWrapping = false）***应该可以，但是我尝试了一百万种不同的组合、文档、论坛等。