您可以使用泛型来解决这个问题。

public class ResponseDto<T>{

private T Result;
private Long Status;

...getters and setters....

}

也可以为其他类创建模型：

public class SuccessResult{

private String name;

...getters and setters....

}

现在假装：

@GetMapping(path = "/test", produces = MediaType.APPLICATION_JSON_VALUE)
    public <T> ResponseDto<T> sendRequest(@RequestParam("id") String ID);
}

或...

@GetMapping(path = "/test", produces = MediaType.APPLICATION_JSON_VALUE)
    public ResponseDto<?> sendRequest(@RequestParam("id") String ID);
}

得到响应后，使用对象Map器转换值：

import com.fasterxml.jackson.databind.ObjectMapper;

.....

@Autowired
ObjectMapper objectMapper;

//....your method and logic...

ResponseDto responseDto = sendRequest("1");

String res = null;
String successResponse = null;

if(responseDto.getResult() instanceof String)
{
    res = objectMapper.convert(responseDto.getResult(), String.class);

} else{

    successResponse = objectMapper.convert(responseDto.getResult(), SuccessResult.class);

}