rust 在对结构使用单独的序列化程序时如何访问主序列化程序

m4pnthwp 于 2023-03-02 发布在其他

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当我为任何数据格式编写序列化程序时，我可以选择为更复杂的类型分离序列化程序。

pub struct Serializer {
    output: String,
}

impl<'a> ser::Serializer for &'a mut Serializer {
     type Ok = ();
     type Error = Error;

     type SerializeStruct = MyStructSerializer; // separate Serializer for structs

     ...
}

如果我采用这种方法，并且需要在复杂类型的序列化程序中序列化基本类型，则需要调用serialize（）并引用主序列化程序，而主序列化程序在那里不可用。

pub struct MyStructSerializer {
}

impl<'a> ser::SerializeStructVariant for &'a mut MyStructSerializer {
    type Ok = Value;
    type Error = Error;

    fn serialize_field<T>(&mut self, key: &'static str, value: &T) -> Result<()>
    where
        T: ?Sized + Serialize,
    {
        key.serialize(&mut **self)?; // Need reference to Serializer here
        value.serialize(&mut **self)?; // Need reference to Serializer here
        Ok(())
    }
    ...
}

我该怎么办？

rust

来源：https://stackoverflow.com/questions/75570798/how-to-access-the-main-serializer-when-using-a-separated-serializer-for-structs

1条答案

按热度按时间

eiee3dmh1#

您可以在MyStructSerializer中引用序列化器：

pub struct MyStructSerializer<'a> {
    serializer: &'a mut Serializer,
}

impl<'a> ser::Serializer for &'a mut Serializer {
    type Ok = ();
    type Error = Error;

    type SerializeStruct = MyStructSerializer<'a>; // separate Serializer for structs

    // ...

    fn serialize_struct_variant(
        self,
        name: &'static str,
        variant_index: u32,
        variant: &'static str,
        len: usize,
    ) -> Result<Self::SerializeStructVariant, Self::Error>
    {
        MyStructSerializer { serializer: self }
    }
    // ...
}

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rust 在对结构使用单独的序列化程序时如何访问主序列化程序

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