如果其中一个是另一个的前缀，则regex findall overlapped不给予匹配

a14dhokn 于 2023-03-04 发布在其他

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import regex

product_detail = "yyy target1 target2 xxx".lower()
p1 = r"\btarget1\b|\btarget1 target2\b"
p2 = r"\btarget2\b|\btarget1 target2\b"
for pattern in [p1, p2]:
    matches = regex.findall(pattern, product_detail, overlapped=True)
    print(matches)

为什么来自p1的匹配只给予['target1']作为输出，而不提供'target1 target2'
但是来自P2的匹配可以成功地给予['target1 target2', 'target2']作为输出。
另外，如果你能提供一个修复，我如何概括它？我有一个10000个目标单词的列表，它不会是可行的硬编码。

regex

来源：https://stackoverflow.com/questions/75563523/regex-findall-overlapped-does-not-give-match-if-one-of-them-is-a-prefix-of-the-o

1条答案

按热度按时间

x4shl7ld1#

下面是一个例子，说明了我对构建一个分隔公共前缀的模式列表的看法：

import regex  # I'm actually using re (don't have regex)

product_detail = "yyy target1 target2 xxx".lower()

keywords = ["target1","target2","target1 target2","target3"]

from itertools import accumulate, groupby, zip_longest

keywords.sort()
groups   = accumulate(keywords,lambda g,k:g if k.startswith(g) else k)
patterns = ( g for _,(*g,) in groupby(keywords,lambda _:next(groups)) )
patterns = ( filter(None,g) for g in zip_longest(*patterns) )   
patterns = [r"\b" + r"\b|\b".join(g) + r"\b" for g in patterns]

# [r'\btarget1\b|\btarget2\b|\btarget3\b', r'\btarget1 target2\b']

for pattern in patterns:
    matches = regex.findall(pattern, product_detail)
    print(matches)

输出：

['target1', 'target2']
['target1 target2']

赞(0）回复(0）举报 2023-03-04

我来回答

如果其中一个是另一个的前缀，则regex findall overlapped不给予匹配

1条答案

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