我想获取www.example.com，因为我必须将其传递给AppConfig.ready（）中的调度程序，但它给出了一个错误。我该怎么做？request.user.id as I have to pass it to scheduler in AppConfig.ready() but it gave an error. How can I do it ?
我的代码如下：

class ApiConfig(AppConfig):
    name = 'myapp'

    def ready(self, request):
        print('Here starting scheduler')
        
        from . import msgScheduler
        user_id = request.user.id

        msgScheduler.start(self,request, user_id)