我在解密加密消息时遇到这个错误,我从django views的数据库中提取了加密消息pw = donator.objects.filter(emai=email).values('passw')
,并在decrypt_message()函数中传递了pw对象,decrypt_messag()函数是:
def decrypt_message(encrypted_message,key):
"""
Decrypts an encrypted message
"""
f = Fernet(key)
decrypted_message = f.decrypt(encrypted_message)
return decrypted_message.decode()
错误消息为:
File "C:\Users\Neelesh Singh\workspace\BookHouse\donatorapp\views.py", line 129, in decrypt_message
f = Fernet(key)
File "C:\Users\Neelesh Singh\AppData\Local\Programs\Python\Python39\lib\site-packages\cryptography\fernet.py", line 37, in __init__
key = base64.urlsafe_b64decode(key)
File "C:\Users\Neelesh Singh\AppData\Local\Programs\Python\Python39\lib\base64.py", line 131, in urlsafe_b64decode
s = _bytes_from_decode_data(s)
File "C:\Users\Neelesh Singh\AppData\Local\Programs\Python\Python39\lib\base64.py", line 45, in _bytes_from_decode_data
raise TypeError("argument should be a bytes-like object or ASCII "
TypeError: argument should be a bytes-like object or ASCII string, not 'dict'
1条答案
按热度按时间8ftvxx2r1#
您应该将与
passw
关联的项传递给函数,因此: