linq C#将对象序列化为包含对象列表的XML

hmae6n7t 于 2023-03-05 发布在 C#

关注(0)|答案(3)|浏览(174)

我需要序列化一个XML，以便为APIPUT请求附加。
我使用的是System.Xml.Serialization。
最终结果需要类似于以下内容：

<?xml version="1.0" encoding="UTF-8"?>
<prestashop xmlns:xlink="http://www.w3.org/1999/xlink">
        <product>
            <id>
                <![CDATA[2678]]>
            </id>
            <cache_default_attribute>
                <![CDATA[0]]>
            </cache_default_attribute>
            <id_shop_default>
                <![CDATA[1]]>
            </id_shop_default>
            <reference>
                <![CDATA[2678]]>
            </reference>
            <supplier_reference>
                <![CDATA[]]>
            </supplier_reference>
            <location>
                <![CDATA[]]>
            </location>
            <width>
                <![CDATA[0.000000]]>
            </width>
            <height>
                <![CDATA[0.000000]]>
            </height>
            <depth>
                <![CDATA[0.000000]]>
            </depth>
            <weight>
                <![CDATA[0.000000]]>
            </weight>
            <quantity_discount>
                <![CDATA[0]]>
            </quantity_discount>
            <ean13>
                <![CDATA[]]>
            </ean13>
            <isbn>
                <![CDATA[]]>
            </isbn>
            <upc>
                <![CDATA[0]]>
            </upc>
            <mpn>
                <![CDATA[000.018]]>
            </mpn>
            <cache_is_pack>
                <![CDATA[0]]>
            </cache_is_pack>
            <cache_has_attachments>
                <![CDATA[0]]>
            </cache_has_attachments>
            <is_virtual>
                <![CDATA[0]]>
            </is_virtual>
            <state>
                <![CDATA[1]]>
            </state>
            <additional_delivery_times>
                <![CDATA[1]]>
            </additional_delivery_times>
            <delivery_in_stock>
                <language id="1">
                    <![CDATA[]]>
                </language>
                <language id="2">
                    <![CDATA[]]>
                </language>
            </delivery_in_stock>
            <delivery_out_stock>
                <language id="1">
                    <![CDATA[]]>
                </language>
                <language id="2">
                    <![CDATA[]]>
                </language>
            </delivery_out_stock>
            <product_type>
                <![CDATA[combinations]]>
            </product_type>
            <on_sale>
                <![CDATA[0]]>
            </on_sale>
            <online_only>
                <![CDATA[0]]>
            </online_only>
            <date_add>
                <![CDATA[2023-02-16 00:21:12]]>
            </date_add>
            <date_upd>
                <![CDATA[2023-02-22 17:22:23]]>
            </date_upd>
            <name>
                <language id="1">
                    <![CDATA[ETNIES TRI LAM POLO (000.018)]]>
                </language>
                <language id="2">
                    <![CDATA[ETNIES TRI LAM POLO (000.018)]]>
                </language>
            </name>
        </product>
</prestashop>

为此我有这样一个类：

[XmlType("product")]
public class Product
{
    public Product()
    {
        id = "";
        active = "1";
        available_for_order= "1";
        indexed= "1";
        visibility = "both";
        delivery_in_stock = new List<PaLanguage>();
        delivery_out_stock = new List<PaLanguage>();
        name = new List<PaLanguage>();
    }

    [XmlElement("id")] public XmlCDataSection C_id { get { return new XmlDocument().CreateCDataSection(id); } set { id = value.Value; } }
    [XmlIgnore] public string id;
    [XmlElement("cache_default_attribute")] public XmlCDataSection C_cache_default_attribute { get { return new XmlDocument().CreateCDataSection(cache_default_attribute); } set {cache_default_attribute = value.Value; } }
    [XmlIgnore] public string cache_default_attribute;
    ...
    [XmlArray("delivery_in_stock")] public List<PaLanguage> delivery_in_stock;
    [XmlArray("delivery_out_stock")] public List<PaLanguage> delivery_out_stock;
    ...

PaLanguage为：

public class PaLanguage
{
    [XmlElement("language")] public XmlCDataSection C_language { get { return new XmlDocument().CreateCDataSection(language); } set { language = value.Value; } }
    [XmlIgnore] public string language { get; set; }
    [XmlAttribute("id")] public string id;
}

因为这是在更新一条记录，所以我首先完成一个get请求，然后匹配它的所有值。

XDocument getResponse = Helper.GetProductReference(get, Helper.GetValueByKey("ShopApi") + "products/");
var gotProduct = getResponse
    .Element("prestashop")
    .Element("products")
    .Elements("product")
    .Where(e => e.Element("reference").Value == mtrl)
    .Single();

我创建了一个新的Product项以附加到我的put请求，但在序列化它的XmlArrays时遇到了问题。
我尝试的最后一件事是：

foreach (XElement x in gotProduct.Element("delivery_in_stock").Elements("language"))
{
    product.delivery_in_stock.Add(new PrestaLanguage { id = (string)x.Attribute("id"), language = (string)x.Element("language") });
}

这是完全错误的，因为它将其序列化为：

<product>
<id><![CDATA[2678]]></id>
... xml
<delivery_in_stock>
  <PaLanguage id="1">
    <language><![CDATA[]]></language>
  </PaLanguage>
  <PaLanguage id="2">
    <language><![CDATA[]]></language>
  </PaLanguage>
</delivery_in_stock>

这感觉就像我已经尝试了一切可以找到网上和官方文件，只有得到进一步从我的预期结果与每一次尝试。
我应该注意到这个类实际上还有几十个字段，它们要么都是字符串，要么都是id和语言值的另一种组合。
任何和所有的帮助是感激的。

linq

来源：https://stackoverflow.com/questions/75545868/c-sharp-serializing-an-object-into-xml-that-includes-a-list-of-objects

3条答案

按热度按时间

vdgimpew1#

XML中的delivery_in_stock和delivery_out_stock元素似乎可以包含具有不同id属性的多种语言元素，因此，需要修改foreach循环以处理多种语言元素。
除了使用Elements（“language”），您还可以使用Descendants（“language”）来获取delivery_in_stock和delivery_out_stock下的所有语言元素。

foreach (XElement x in gotProduct.Element("delivery_in_stock").Descendants("language"))
{
    product.delivery_in_stock.Add(new PaLanguage { id = (string)x.Attribute("id"), language = (string)x });
}

foreach (XElement x in gotProduct.Element("delivery_out_stock").Descendants("language"))
{
    product.delivery_out_stock.Add(new PaLanguage { id = (string)x.Attribute("id"), language = (string)x });
}

此外，在PaLanguage类中，language属性的类型应为XmlCDataSection，而不是string，因为它包含CDATA。

public class PaLanguage
{
    [XmlText]
    public XmlCDataSection language { get; set; }

    [XmlAttribute("id")]
    public string id { get; set; }
}

最后，对于产品类，应该将[XmlElement]属性添加到没有这些属性的属性中，例如id_shop_default、reference、supplier_reference等。

[XmlType("product")]
public class Product
{
    public Product()
    {
        id = "";
        active = "1";
        available_for_order = "1";
        indexed = "1";
        visibility = "both";
        delivery_in_stock = new List<PaLanguage>();
        delivery_out_stock = new List<PaLanguage>();
        name = new List<PaLanguage>();
    }

    [XmlElement("id")]
    public XmlCDataSection C_id { get { return new XmlDocument().CreateCDataSection(id); } set { id = value.Value; } }

    [XmlElement("cache_default_attribute")]
    public XmlCDataSection C_cache_default_attribute { get { return new XmlDocument().CreateCDataSection(cache_default_attribute); } set { cache_default_attribute = value.Value; } }

    [XmlElement("id_shop_default")]
    public XmlCDataSection C_id_shop_default { get { return new XmlDocument().CreateCDataSection(id_shop_default); } set { id_shop_default = value.Value; } }

    [XmlElement("reference")]
    public XmlCDataSection C_reference { get { return new XmlDocument().CreateCDataSection(reference); } set { reference = value.Value; } }

    [XmlElement("supplier_reference")]
    public XmlCDataSection C_supplier_reference { get { return new XmlDocument().CreateCDataSection(supplier_reference); } set { supplier_reference = value.Value; } }

    [XmlElement("location")]
    public XmlCDataSection C_location { get { return new XmlDocument().CreateCDataSection(location); } set { location = value.Value; } }

    [XmlElement("width")]
    public XmlCDataSection C_width { get { return new XmlDocument().CreateCDataSection(width); } set { width = value.Value; } }

    [XmlElement("height")]
    public XmlCDataSection C_height { get { return new XmlDocument().CreateCDataSection(height); } set { height = value.Value; } }

// etc..

赞(0）回复(0）举报 2023-03-05

yxyvkwin2#

你能做的是用下面的PaLanguage替换你当前的PaLanguage，并尝试在你发现问题的所有字段上做同样的事情：

[XmlElement(ElementName = "language")]
public class PaLanguage
{
    [XmlText] 
    public string value { get; set; }
    [XmlAttribute("id")] 
    public string id;
}

赞(0）回复(0）举报 2023-03-05

sg24os4d3#

我在正确的轨道上

public class PaLanguage
{
    [XmlElement("language")] public XmlCDataSection C_language { get { return new XmlDocument().CreateCDataSection(language); } set { language = value.Value; } }
    [XmlIgnore] public string language { get; set; }
    [XmlAttribute("id")] public string id;
}

首先，我将C_language更改为XmlNode[]，其中getter和setter稍有不同

public class PaLanguage
{
    [XmlText] public XmlNode[] C_language 
        { 
            get { var dummy = new XmlDocument();  return new XmlNode[] { dummy.CreateCDataSection(language) }; } 
            set { var dummy = (XmlCDataSection)value[0]; language = dummy.Data; } 
        }
    [XmlIgnore] public string language { get; set; }
    [XmlAttribute("id")] public string id;
}

然后我还更改了Product中的列表

[XmlArray("delivery_in_stock")] [XmlArrayItem("language")] public List<PaLanguage> delivery_in_stock;
[XmlArray("delivery_out_stock")] [XmlArrayItem("language")] public List<PaLanguage> delivery_out_stock

最后，正如塞巴斯蒂安建议的那样，我使用了后代而不是元素。

foreach (XElement x in gotProduct.Element("delivery_in_stock").Descendants("language"))
                        {
                            product.delivery_in_stock.Add(new PrestaLanguage { id = (string)x.Attribute("id"), language = (string)x.Element("language") });
                        }
                        foreach (XElement x in gotProduct.Element("delivery_out_stock").Descendants("language"))
                        {
                            product.delivery_out_stock.Add(new PrestaLanguage { id = (string)x.Attribute("id"), language = (string)x.Element("language") });
                        }

感谢所有帮忙的人。

赞(0）回复(0）举报 2023-03-05

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linq C#将对象序列化为包含对象列表的XML

3条答案

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