使用Collections.lastIndexOfSubList检查列表是否包含子列表，如果它确实获得了最后一个索引，则删除从最大索引开始向后迭代的元素：

List<String> list = new ArrayList<>(List.of("Some text",
                                            "Some more text",
                                            "",
                                            "Line a",
                                            "Line b",
                                            "",
                                            "Line c",
                                            "Line d"));

List<String> target = List.of("", "Line c", "Line d");

while (Collections.lastIndexOfSubList(list, target) != -1) {
    int lastIndex = Collections.lastIndexOfSubList(list, target);
    for (int i = target.size() - 1; i >= 0; i--) {
        list.remove(lastIndex + i);
    }
}

只需检查接下来的3个值，以确定是否需要保留它们

List<String> a = new ArrayList<>(List.of("Some text", "Some more text",
        "", "Line a", "Line b",
        "", "Line c", "Line d",
        "Line a", "Line b",
        "", "Line c", "Line d"));
for (int i = 0; i < a.size() - 2; i++) {
    if (a.get(i).equals("") && a.get(i + 1).equals("Line c") && a.get(i + 2).equals("Line d")) {
        a.remove(i);
        a.remove(i); // has everybody has move forward once, "Line c" if one forward too
        a.remove(i); // same
    }
}

System.out.println(a);
// [Some text, Some more text, , Line a, Line b, Line a, Line b]

条件也可能是

if (a.subList(i, i + 3).equals(List.of("", "Line c", "Line d")))